What Is the Ratio of Ms to Mc?

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    Inertia
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Homework Help Overview

The problem involves calculating the ratio of the mass of a square object to the mass of a circle that is cut out from its center, as well as expressing the moment of inertia in terms of these masses and the dimensions of the object. The subject area includes concepts of rotational dynamics and geometry.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to find the ratio of the mass of the square to the mass of the circle by comparing their areas, leading to a ratio of 4:π. Some participants engage with this reasoning, suggesting it is a reasonable approach.

Discussion Status

Participants are actively discussing the ratio of the masses and how it relates to the overall mass of the object. There is acknowledgment of the original poster's calculations, and some guidance is offered regarding expressing the masses in terms of the total mass.

Contextual Notes

The original poster expresses uncertainty about their understanding of ratios and the implications of their findings for subsequent parts of the problem. There is a focus on ensuring the accuracy of the ratio before proceeding further.

WhoThat3
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Hey so I got stuck on this question and was wondering if I can get some help. I got up to part c, but I am not sure about it. Also for part a I am not sure if I used the right equations for Inertia. Here it is.

Homework Statement


An object in the shape of a square with a circle cut in the center of it spins about its center of mass. The axis of rotation is perpendicular to the plane of the square. The object has mass M and has edges of length 2R. ITs density is constant.

Picture:
A Square with an inscribed circle of radius R both with the same center.


a) Ms = mass of whole squaer; Mc = mass of circle that was cut out.
Express Moment of Inertia in terms of Ms, Mc, and R.

b)How does the object's mass relate to the masses Ms and Mc?(Equation)

c) What is the ratio of Ms to Mc? *****

d) Use answer from part b and c to express Ms and Mc each in terms of M.

e) Express Moment of Inertia in terms of M and R.

Homework Equations



I = 1/2*MR^2

I=1/12*M(L^2 + W^2)


The Attempt at a Solution



a) Icircle=1/2*MR^2
Isquare=1/12*M((2R)^2+(2R)^2)

Itogether=Isquare-Icircle
I=2/3*MsR^2-1/2*McR^2
I=R^2*(2/3*Ms-1/2*Mc) -- answer for part A

b) M=Msquare-Mcircle

c) Ok here is my probelm, I never was good with ratios, but I did try to find their areas; Asquare = 4R^2 and Acircle = R^2*pi and if I made those in a ratio I get a 4:pi ratio, which is close to 4:3 which does seem reasonable. But I just want to double check. I have not gone on since the other parts fo this question depend on this one. Thanks again
 
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u are correct i guess. ratio of mass of sq to circle is 4:pi. M=Mc+Ms, so find the ratio of Ms and Mc to M. for last part, replace Ms and Mc by M
 
WhoThat3 said:
c) Ok here is my probelm, I never was good with ratios, but I did try to find their areas; Asquare = 4R^2 and Acircle = R^2*pi and if I made those in a ratio I get a 4:pi ratio, which is close to 4:3 which does seem reasonable.
You are correct.
 
Great, thanks for the reply, I just wanted to double check.
 

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