What is the Ray Tracing Diagram for a Concave Lens with f < do < R?

Click For Summary
SUMMARY

The discussion centers on creating a ray tracing diagram for a concave lens under the condition where the object distance (do) is between the focal length (f) and the radius of curvature (R). The user correctly identifies the focal length as 5cm, leading to a radius of curvature of 10cm. By selecting an object distance of 7.5cm, they apply the lens formula (1/do + 1/di = 1/f) to find the image distance (si) as 0.15m, resulting in a magnification (M) of -2, indicating a real, inverted, and magnified image.

PREREQUISITES
  • Understanding of ray tracing techniques for lenses
  • Familiarity with the lens formula: 1/do + 1/di = 1/f
  • Knowledge of magnification calculations (M = -di/do)
  • Basic concepts of concave lenses and their properties
NEXT STEPS
  • Study ray tracing diagrams for various lens types
  • Learn about the properties of concave lenses and their image formation
  • Explore the impact of varying object distances on image characteristics
  • Investigate the relationship between focal length and radius of curvature in lenses
USEFUL FOR

Students studying optics, physics educators, and anyone interested in understanding lens behavior and ray tracing techniques.

chrisfnet
Messages
38
Reaction score
0

Homework Statement



I have a concave lens where f < do < R. I have to provide a ray tracing diagram.

The Attempt at a Solution



I drew the focal ray through the focus and parallel to the principal axis. I drew the principal ray parallel to the principal axis then through the focus. I drew a dashed line from the center past the object tip and to the lens.

This leads to a diagram where there are no converging lines. However, if I arbitrarily choose some numbers to confirm this... this is where I get confused.

I'll choose a focal length (f) of 5cm. This means that R must be 2f. So, R = 10cm.

I'll choose an so between 5cm and 10cm of 7.5cm.

Given that:

1/so + 1/si = 1/f

1/0.075m + 1/si = 1/0.05m

si = 0.15m

M = -0.15m/0.075m = -2

This is telling me that I have a real image that is inverted and magnified by a factor of two.

Confused. Any help would be appreciated.
 
Physics news on Phys.org
Does your diargam look anything like this?

http://kottan-labs.bgsu.edu/teaching/workshop2001/chapter2_files/image008.gif
 
Last edited by a moderator:

Similar threads

Analyzing this 2-lens optical system
  • · Replies 5 ·
Replies
5
Views
2K
Is the image upright for a reflective spherical balloon using ray tracing?
  • · Replies 1 ·
Replies
1
Views
1K
Calculate a radius of a circle on a screen
  • · Replies 3 ·
Replies
3
Views
1K
Calculating Chromatic Aberration
  • · Replies 2 ·
Replies
2
Views
2K
Undergrad Image construction with concave and convex mirrors
  • · Replies 4 ·
Replies
4
Views
2K
Multiple Lens System(Objectless and Parallel Rays)
  • · Replies 2 ·
Replies
2
Views
2K
Image Distance with two concave lenses
  • · Replies 4 ·
Replies
4
Views
4K
Ray Tracing and Lens Formula for Image Location
  • · Replies 7 ·
Replies
7
Views
2K
Ray diagram diverging lens both object and image virtual
  • · Replies 2 ·
Replies
2
Views
3K
Understanding Two Convex Lenses: Ray Diagram and Focal Lengths
  • · Replies 3 ·
Replies
3
Views
2K