What is the relationship between refractive index and pressure in gases?

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Homework Help Overview

The discussion revolves around the relationship between the refractive index and pressure in gases, specifically focusing on the equation n_r = 1 + K × p. Participants are exploring how the refractive index, which is close to 1 in gases, varies with pressure and the implications of the Clausius-Mossotti equation in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to connect the Clausius-Mossotti equation to the refractive index equation and are questioning which quantities in the equations depend on pressure. There is also discussion about the relevance of the ideal gas law in deriving the relationship.

Discussion Status

The discussion is active, with participants providing insights and questioning each other's reasoning. Some guidance has been offered regarding the ideal gas law and its relationship to density and pressure, although there is no explicit consensus on the approach to take.

Contextual Notes

There is some confusion regarding the application of the Clausius equation and the ideal gas law, with participants expressing uncertainty about the necessity of these equations for solving the problem.

Aeon
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Dependence of refractive index on pressure

Homework Statement


Show that, in a gas (for which the refractive index is close to 1), the refractive index depends on the pressure as n_r = 1+ K\times p, and find the value of K.

Homework Equations



n_r = 1+ K\times p
Clausius-Mossotti equation: \frac{\epsilon_r - 1}{\epsilon_r + 2} = \frac{\rho N_a \alpha}{3M\epsilon_0}
\alpha^'\ = \frac{\alpha}{4\pi \epsilon_0}
n_r = \epsilon_r^{1/2}

The Attempt at a Solution



Any help to get me started, conceptual or mathematical, will be appreciated!

PS: I think I have posted this question in the right forum now. I had posted it in Advanced Physics before... I would have deleted my other post, but I can't.
 
Last edited:
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Which quantity on the right-hand side depends on the pressure p?

ehild
 
Supposing you're talking about the Clausius equation, I would say \frac{\rho}{M} = \frac{1}{V_m} depends on the pressure (inversely to how it behaves in phase diagrams).
 
The problem confuses me. I don't understand how I can go from the Clausius equation to <br /> n_r = 1+ K\times p<br />
 
Think of the ideal gas law. What is the relation between density and pressure?

ehild
 
i got confused
 
\rho = \frac{mp}{nRT}

To be honest, I'm starting to think I don't even NEED the Clausius equation to solve this problem...

Do I?
 
You do. Check the ideal gas law. It is wrong as you wrote it.
The symbol n in the ideal gas low means number of moles, n= mass/molar mass. And look after the meaning of the symbols in the Clausius equation.

ehild
 

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