What is the relationship between speed and radius for a car to avoid skidding?

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Homework Help Overview

The discussion revolves around the relationship between speed and radius for a car navigating a curve without skidding, focusing on the implications of changing speed on the required radius to maintain traction.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the mathematical relationship between speed and radius, particularly how doubling speed affects the radius needed to avoid skidding, referencing the equation f = mV²/R.

Discussion Status

Some participants have provided insights into the squared nature of velocity in the equation, leading to a deeper understanding of how the radius must change. There is an acknowledgment of the role of static friction as a limiting factor in this scenario.

Contextual Notes

Participants are discussing the maximum value of static friction and its implications for centripetal force in the context of the problem.

Jeann25
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If a certain car, going with speed v, rounds a level curve with a radius R, it is just on the verge of skidding. If its speed is now doubled, the radius of the tightest curve on the same road that it can round without skidding is:

Answer is 4R.. but I don't understand why?

I know the equation is f = mV²/R
 
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in the equation, the velocity is squared.

if the velocity becomes 2V, when you square it, it becomes 4V^2. to keep the car from skidding, the radius now has to change to 4r
 
Also, it is important to understand that the static friction, the source of the net centripetal force, is at its maximum value, and does not change.
 
I get it now. Thank you! :smile:
 

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