- #1
Joe Cruz
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1. A car travels around a circle with a diameter of 500m at a constant speed of 25 m/s. The static friction coefficient is 0.3 and the kinetic friction coefficient is 0.2. Will the car skid?
2. F = ma. Ffr = μmg. Centripetal acceleration = v2/radius3. So the math for this particular problem was really simple, my problem seems to be more of a conceptual one.
The force acting on the car = F = m(252/250) = m(2.5)
The static friction force = Fsfr = m(.3)(9.8) = m(2.94)
The kinetic friction force = Fkfr = m(.2)(9.8) = m(1.96)
My first assumption is that the car is going to skid since the car is moving and the force acting on the car exceeds the kinetic friction force, but since Fkfr < F < Fsfr, I'm not entirely sure if this is the correct answer. Anyone want to help clarify this problem for me?
2. F = ma. Ffr = μmg. Centripetal acceleration = v2/radius3. So the math for this particular problem was really simple, my problem seems to be more of a conceptual one.
The force acting on the car = F = m(252/250) = m(2.5)
The static friction force = Fsfr = m(.3)(9.8) = m(2.94)
The kinetic friction force = Fkfr = m(.2)(9.8) = m(1.96)
My first assumption is that the car is going to skid since the car is moving and the force acting on the car exceeds the kinetic friction force, but since Fkfr < F < Fsfr, I'm not entirely sure if this is the correct answer. Anyone want to help clarify this problem for me?