What is the Relationship Between Work, Distance, Power, and HP?

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Homework Help Overview

The discussion revolves around the relationship between work, distance, power, and horsepower in the context of lifting an object at a constant speed. Participants are exploring the relevant equations and concepts related to these physical quantities.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equations involved, such as W=fd and F=ma, while questioning the necessary variables like force and acceleration. There is an acknowledgment of the need to convert units and the implications of lifting at constant speed.

Discussion Status

Some participants have provided guidance on the equations and assumptions, such as the force being equal to the weight of the object when lifted at constant velocity. Multiple interpretations of the problem are being explored, particularly regarding the variables involved.

Contextual Notes

There is mention of unit conversion from feet to meters, and participants express uncertainty about the values of force and acceleration, indicating potential gaps in information needed to proceed.

Klane
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nijh
 
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You have the right equations, so just solve. The assumption is that the lifting is done at a constant speed. What force does the lifter apply?
 
you need to convert feet to meters, 1 foot = 0.3048 meters. Then just apply your equations.
 
Well I know that W=fd. I have d but not f and I know the equation for f is F=ma, but I don't have a. It seems like I'm going in circles..sorry, I take forever with this.
 
The force needed to lift an object at constant velocity is equal to its weight ;), you DO know the force!
 

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