What is the Resistance of a 1 km Composite Copper-Steel Wire?

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Homework Help Overview

The problem involves calculating the resistance of a composite wire made of copper and steel, with specific dimensions provided for each material's cross-section. The context is rooted in electrical resistance and material properties.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the method of treating the copper and steel layers as resistors in parallel and question the calculations of cross-sectional areas. There is also a discussion about the correct interpretation of the wire's dimensions.

Discussion Status

The discussion is active, with participants providing feedback on calculations and clarifying misunderstandings regarding the wire's geometry. Some guidance has been offered regarding the area calculations, and there is an acknowledgment of a mistake in the original poster's approach.

Contextual Notes

Participants are working with specific resistivity values and dimensions, and there is an emphasis on maintaining accuracy in calculations. The original poster's reference to an answer key suggests a comparison to expected results, which may influence the discussion.

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Homework Statement


A transmission wire is made of a cylindrical core of copper surrounded by a sheath of steel. The copper core is 1 cm in diameter, and the sheath has an outer diameter of 2 cm. What is the resistance of 1 km of wire?


Homework Equations


R=ρl/A


The Attempt at a Solution


I tried treating the two layers of wire as resistors in parallel, so I found the resistance of each one and added them that way (R-1=R1-1+R2-1). For the area of the outer sheath, I used the area of the total wire minus the area of the inner copper part.

Resistance of copper = (1.72e-8 * 1000) / 7.85e-5 = 0.219 ohm
Area of steel part: 7.07e-4 - 7.85e-5 = 6.28e-4 m2
Resistance of steel = (29e-8 * 1000) / 6.28e-4 = 0.46 ohm

Equivalent resistance = (Rcopper-1 + Rsteel-1)-1 = 0.15. But the answer key says it's 0.19. I tried to keep as many decimal places all the way through, and used values for resistivity straight out of the textbook. Any help please?
 
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I think you have mis-calculated the cross sectional area of the steel.
The outside diameter of the steel is 2cm and the inside diameter is 1cm
I got the area to be 3.142 x 10^-4 - 7.86 x 10^-5
This gave a total resistance of 0.186 (0.19)
 
Alright, I see how you did that. but how come you used 1 (half of 2) instead of 1.5 (half of 3, total diameter of the wire) for the first radius?
 
The wire has a central core of diameter 1cm. The steel coating has a diameter of 2cm...it is not 3cm.
Imagine a Doughnut... the hole in the middle is the copper (1cm diameter) the best bit of the doughnut is the steel... diameter 2cm
 
Oh ok silly mistake on my part. Thank you very much.
 
glad you got it... enjoy the doughnut
 

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