What is the Resultant Gravitational Force on the 8 kg Mass?

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The discussion focuses on calculating the resultant gravitational force acting on an 8 kg mass located at the origin due to two other masses: a 7 kg mass at coordinates (-3,1) and a 9 kg mass at (1,2). The universal gravitational constant used is 6.6726 × 10^−11 N·m²/kg². Participants emphasize the importance of using Pythagoras' theorem to find distances and applying the formula F = GMm/r² to determine the gravitational forces from each mass. The principle of linear superposition is crucial for calculating the net force on the 8 kg mass.

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1Three masses are arranged in the (x, y)
plane as shown.

7kg at (-3,1)
8kg at (0,0)
9kg at (1,2)

What is the magnitude of the result-
ing force on the 8 kg mass at the ori-
gin? The universal gravitational constant is
6.6726 × 10^−11 N · m^2/kg^2 . Answer in units
of N.




part 2; Select the figure showing the direction of the
resultant force on the 8 kg mass at the origin. all the mutliple choice aswers show a ray rotating a different amount around the origin




please help, i was sick and missed 2 days of physics and don't understand even wath the question is askeing
if you could even expain it to me it would be wonderful
thanks!
 
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You can calculate the distances from each mass to the 8kg mass by using Pythagoras' theorem.

Force on masses due to gravity is dependent upon each mass as well as radius.

This is the formula: [tex]F = \frac{GMm}{r^2}[/tex]

Use the principle of linear superposition to determine the net force.
 

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