- #1
neu
- 230
- 3
I am a 3rd Physics student and this is news to me!
apparently root of i is exp(iPi/2))^1/2
Why?
Of course by i I mean Root of minus 1
apparently root of i is exp(iPi/2))^1/2
Why?
Of course by i I mean Root of minus 1
neutrino said:-2a^{2} is not equal to 1, for real a.
mathis314 said:how do we know that the sqrt of i can be denoted as a+bi?
mathis314 said:how do we know that the sqrt of i can be denoted as a+bi?
mathis314 said:how do we know that the sqrt of i can be denoted as a+bi?
Well, perhaps he knew that the complex numbers are algebraically closed and so did know that the square root of i is a complex number.Werg22 said:a + bi is the general form of any complex number. This said, stupidmath made the assumption that the square root can be expressed as complex number. He didn't know whether or not this is the case first, but lucky him, it is!
HallsofIvy said:Well, perhaps he knew that the complex numbers are algebraically closed and so did know that the square root of i is a complex number.
Werg22 said:If you did not know it, it would have made the assumption unsure, not necessarily false.
The root of i is a mathematical concept that represents the solution to the equation x^2 = i. It is a complex number that can be expressed as ± (√2/2 + √2/2i).
The value of root of i is approximately 0.707 + 0.707i or -0.707 - 0.707i. It is a complex number that cannot be simplified any further.
The root of i is calculated by solving the equation x^2 = i. This can be done by using the quadratic formula or by using the method of completing the square.
The root of i is significant in mathematics and physics as it is used in various calculations involving complex numbers, such as in electrical engineering and quantum mechanics.
No, the root of i cannot be expressed in simpler terms as it is a complex number that cannot be simplified any further. It is the solution to a specific mathematical equation and has its own unique value and properties.