What is the Set and Probability of Drawing Coins with Replacement?

[magnifik]

A coin purse contains 9 nickels and 1 quarter. Two coins are drawn WITH REPLACEMENT. What is the set S of this random experiment? What are the probabilities of the elementary events?

i'm a little confused by the "with replacement" concept. I'm just wondering if I'm doing it correctly. i have the equation n-1+k choose n-1 so here's my work:

set S = {two nickels, two quarters, one nickel and one quarter}
total possible ways of selection: (10-1+2) choose (10-1) = 55
P[two nickels] = (9-1+2) choose (9-1) / 55 = 45/55
P[two quarters] = (2-1+2) choose (2-1) / 55 = 3/55
P[one nickel and one quarter] = 1 - P_{all other events} = 1 - (45/55 + 3/55) = 7/55

have i done the problem correctly?

 

[MisterX]

What is the probability of drawing a quarter for the first coin? With replacement, would the probability of drawing a quarter the second time be any different?

The results of the coin drawings would be independent events, so what would the probability of drawing two quarters be, in terms of the probabilities of drawing a quarter for the first and second drawings?

 

[magnifik]

What is the probability of drawing a quarter for the first coin? With replacement, would the probability of drawing a quarter the second time be any different?

The results of the coin drawings would be independent events, so what would the probability of drawing two quarters be, in terms of the probabilities of drawing a quarter for the first and second drawings?

probability for drawing a quarter for the first coin = 1/10
probability of drawing a quarter for the second coin = 1/10
so P[drawing 2 quarters] = 1/100 ?

do i follow the same approach for the probability of each of the elementary events? like for 1 nickels..
probability of drawing 1 nickel first = 9/10
probability of drawing 1 nickel second = 9/10
so P[drawing 2 nickels] = 81/100

and then for 1 nickel and 1 quarter
probability of drawing 1 nickel = 9/10
probability of drawing 1 quarter = 1/10
P[1 nickel, 1 quarter] = 9/100

but the probabilities do not add up to 1 so i am still confused :\

 

[Mark44]

Mod note: Moved from Engineering & CS section.

 

[MisterX]

but the probabilities do not add up to 1 so i am still confused :\

There are two ways the two coins drawn would be a nickel and a quarter.

 

[magnifik]

There are two ways the two coins drawn would be a nickel and a quarter.

Ahh, I see. This is because order doesn't matter, correct? so P[1 nickel, 1 quarter] = 9/100 + 9/100 = 18/100 = 9/50