What is the significance of rotation in equations?

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SUMMARY

The discussion centers on the significance of rotation in the context of second order linear homogeneous partial differential equations, specifically focusing on the form a(uxx + uyy) + bu = 0. It is established that for an equation to be rotationally invariant, it must retain its form under arbitrary rotations of the coordinate system. The transformation of coordinates using trigonometric identities is crucial for demonstrating this invariance, as it ensures that no mixed derivative terms, such as uxy, appear in the equation after rotation.

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  • Understanding of second order linear homogeneous partial differential equations
  • Familiarity with coordinate transformations and trigonometric identities
  • Knowledge of the chain rule in calculus
  • Basic concepts of rotational invariance in mathematical equations
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wumple
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This is sort of a homework question but I'm not looking for an answer. I'm just trying to understand exactly what's going on. It says "Among all the equations of the form [the general second order linear homogeneous partial differential equation], show that the only ones that are unchanged under all rotations (rotationally invariant) havce the form a(uxx + uyy) + bu =0.

What exactly does it mean for an equation to be rotated? I don't understand what's going on here very well.
 
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I would guess it means if you rotate the coordinate system through an arbitrary angle, the form of the equation stays the same, i.e. you don't get a uxy term.
 
Let [itex]x= x'cos(\theta)+ y' sin(\theta)[/itex], [itex]y= -x'sin(\theta)+ y'cos(\theta)[/itex], so that [itex]x'= xcos(\theta)- ysin(\theta)[/itex] and [itex]y'= xsin(\theta)+ ycos(\theta)[/itex], and use the chain rule to replace [itex]u_{xx}[/itex] and [itex]u_{yy}[/itex] with derivatives in terms of x' and y' rather than x and y.

For example, [itex]u_x= u_x'(x'_x)+ u_y'(y'_x)= cos(\theta)u_x'+ sin(\theta)u_y'[/itex].
 

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