What is the significance of the A004730 sequence in mathematics?

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Homework Help Overview

The discussion revolves around the significance of the A004730 sequence in mathematics, particularly focusing on the concept of double factorials and their properties.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definition of double factorials, questioning how they relate to standard factorials. There is an attempt to clarify the calculations involving the sequence, with some confusion arising from the interpretation of numerators and denominators in specific examples.

Discussion Status

The discussion is ongoing, with participants sharing insights about double factorials and their calculations. Some have expressed confusion regarding specific entries in the sequence, while others have clarified aspects of the definitions and calculations involved.

Contextual Notes

Participants are referencing a specific online resource for definitions and examples, indicating a reliance on external material for understanding the sequence. There are mentions of confusion regarding the sequence's entries and the nature of double factorials.

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Homework Statement



Can someone explain to me what is this sequence referred in the page?
http://oeis.org/A004730"
 
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It says what it is on the page, right? '!' is 'double factorial'. If n is even n! is the product of all of the even numbers up to n and if n is odd then it's the product of all of the odd numbers. I.e. 5!/6!=(1*3*5)/(2*4*6)=5/16. Then take the numerator. That's the 5 entry.
 
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Thanks! =D I didnt know there is a double factorial
 
Now I'm confused. 4!/5! should be 2*4/(3*5)=8/15. I don't see a 15 in the series.
 
Dick said:
Now I'm confused. 4!/5! should be 2*4/(3*5)=8/15. I don't see a 15 in the series.

Never mind. I was looking at the denominator instead of the numerator.
 
The series has included both numerator and denominator... So its Ok! =D
 
These "double factorials" can always be written in terms of the usual factorial:

If n is even, say n= 2k, then
[itex]n!= 2(4)(6)...(2k-2)(2k)= (2(1))(2(2))(2(3))...(2(k-1))(2k)= 2^k k![/tex]<br /> <br /> If n is odd, say n= 2k+ 1, then <br /> [tex]n!= 3(5)(7)...(2k-1)(2k+1)= \frac{2(3)(4)(5)(6)(7)...(2k-1)(2k)(2k+1)}{2(4)(6)...(2k)}[/tex]<br /> [tex]= \frac{(2k+1)!}{2^k k!}[/tex][/itex]
 

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