What is the significance of the x in the chemical formula (Mo6S9-xIx)?

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The chemical formula Mo6S9-xIx represents inorganic molecular nanowires, where 'x' indicates the number of iodine (I) atoms present, while the remaining atoms are sulfur (S). This formula allows for variations in stoichiometric ratios, enabling the study of different compounds with identical crystal structures. The range of 'x' is typically specified in experimental studies, affecting the molecular packing and stability of the nanowires. Notably, variations in 'x' are limited due to the size difference between iodine and sulfur, which can introduce strains that destabilize the structure.

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lo2
On

http://en.wikipedia.org/wiki/Nanowire"

This sentence.

For example, inorganic molecular nanowires (Mo6S9-xIx) have a diameter of 0.9 nm, and can be hundreds of micrometers long.

What is (Mo6S9-xIx) I know it is a chemical formula for a molecule but what do those x'ses mean?
 
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lo2 said:
On

http://en.wikipedia.org/wiki/Nanowire"

This sentence.

For example, inorganic molecular nanowires (Mo6S9-xIx) have a diameter of 0.9 nm, and can be hundreds of micrometers long.

What is (Mo6S9-xIx) I know it is a chemical formula for a molecule but what do those x'ses mean?
It appears to be written Mo6S9-xIx. In that case, the wire would contain x atoms of I and 9-x atoms of S.

For example, 6 I atoms would yield Mo6S3I6. It probably has to do with molecular packing.
 
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The index "x" is used to refer to a series of compounds with the same elements (and likely, identical crystal structures) but different stoichimetric ratios between the elements. Very likely, you will find that the original source of any study on these compounds will specify the range of values that x was made to take in the experiment. You can then plug in those values and calculate the compositions as geoff has shown above.

Extra note: Since Iodine is about 30% bigger than Sulfur, I don't imagine you can vary x by a whole lot (maybe a range of 1 or 2) without introducing large strains that will destabilize the wire.
 

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