What is the slope of a force vs. distance graph?

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SUMMARY

The slope of a Force vs. Distance graph is not acceleration but rather represents surface tension, as indicated by the units of N/m. The area under the curve corresponds to work, calculated using the equation W=Fd. To determine the velocity at any distance, one must calculate the area under the graph, which equates to work, and then apply the conservation of energy principle, leading to the kinetic energy equation S = 1/2 mv².

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Homework Statement


What is represented by the slope of a Force vs. Distance graph?

Also, if I had a Force vs. Distance graph and knew my initial velocity was some value, how would I go about finding the velocity at any distance along the way?

Homework Equations


F=ma

W=Fd

v=d/t

The Attempt at a Solution


I know that the area under the curve of a Force vs. Distance graph represents work (W=Fd). Is the slope of a Force vs. Distance graph *acceleration*?
 
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Consider the units.

Units of Force = Newtons
Units of distance = meters

So the slope of an F/D plot would be N/m wouldn't it?

What do you know that has N/m as its units? Does anything spring to mind?
 
N = m∙kg/s²
m = m

N/m = kg/s² = surface tension (slope of Force vs. Distance graph)

Ok thanks for helping me think. Rise over run... Units of y-axis over units of x axis. That makes sense.

For the other part of my question, I think I've got it under wraps. To find the velocity at a certain distance of a Force vs. Distance graph, I need to:

Calculate area S below the graph.
This area is work, because it is equal to
S = integral of F(x)dx = integral of d(work)

Using conservation of energy I can now find the velocity:
S = Work = KE = 1/2 mv²
 

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