Discussion Overview
The discussion revolves around calculating the solubility of Al(OH)3 in a solution of 0.0010 M Al(NO3)3, focusing on the implications of the common ion effect on the solubility product constant (Ksp). The scope includes homework-related problem-solving and mathematical reasoning.
Discussion Character
- Homework-related
- Mathematical reasoning
- Technical explanation
Main Points Raised
- One participant states the Ksp of Al(OH)3 is 1.0 x 10-33 and expresses confusion about how the 0.0010 M Al(NO3)3 will dissociate and affect the Ksp.
- Another participant points out a mistake in the initial calculation and prompts for clarification on the Ksp formula for Al(OH)3.
- A subsequent reply questions the placement of the coefficient in the Ksp expression and provides the correct formula: Ksp = [Al3+][OH-]3.
- Further, a participant suggests that if the concentration of dissolved Al(OH)3 is x, the concentrations of Al3+ and OH- need to be determined, considering the initial concentration of Al3+ already present.
- Another participant emphasizes that the dissolution of Al(OH)3 adds to the existing ion concentrations and suggests that approximations regarding negligible differences will be addressed later.
Areas of Agreement / Disagreement
Participants do not reach a consensus on the correct approach to the problem, as there are multiple interpretations of how to apply the Ksp and the effects of the common ion. Disagreements arise regarding the correct formulation and calculation steps.
Contextual Notes
Participants express uncertainty about the correct application of the Ksp formula and the implications of the common ion effect on solubility. There are unresolved mathematical steps and assumptions regarding the concentrations of ions in solution.