What is the solution for Ry in Sin 0=Ry/Rx when given values for Rx and theta?

[niknak98]

Teacher assigned this on first day due tomorrow and i have no clue on some like this one:

Sin 0=Ry/Rx a.) solve for Ry
b.) solve for Rx
c.) solve for 0

?

 

[Student100]

Is there anymore information you can provide? Is that actually Sin(0)? Did you attempt to solve it on your own? Have you tried the inverse function?

Anyway, if it really is 0 then it should be obvious. Ry would have to be zero. Rx is then any real which is not equal to zero. Rewriting the equation as arcsin(Ry/Rx) = 0 will demonstrate this as well. I'm saying this because part of me doesn't believe that is really supposed to be sin(0), instead it's probably theta.

 

[HallsofIvy]

I can make absolutely no sense out of "solve for 0"! That would be like saying "solve for 2".

I strongly suspect that was supposed to be $sin(\theta)= R_y/R_x$ and your teacher (or you!) missed the horizontal line on the $\theta$.

To "solve for y", multiply both sides by $R_x$. To "solve for x" one method is to first invert both sides, getting $1/sin(\theta)= R_x/R_y$ and then multiply both sides by $R_y$. To "solve for $\theta$" take the inverse sin (arcos or $sin^{-1}$) of both sides.

 

[niknak98]

I can make absolutely no sense out of "solve for 0"! That would be like saying "solve for 2".

I strongly suspect that was supposed to be $sin(\theta)= R_y/R_x$ and your teacher (or you!) missed the horizontal line on the $\theta$.

To "solve for y", multiply both sides by $R_x$. To "solve for x" one method is to first invert both sides, getting $1/sin(\theta)= R_x/R_y$ and then multiply both sides by $R_y$. To "solve for $\theta$" take the inverse sin (arcos or $sin^{-1}$) of both sides.

Thanks this really helped and he did correct it that the 0 was theta