What is the solution for Ry in Sin 0=Ry/Rx when given values for Rx and theta?

  • Thread starter Thread starter niknak98
  • Start date Start date
  • Tags Tags
    Sin
Click For Summary

Homework Help Overview

The discussion revolves around a trigonometric equation involving sine, specifically the relationship Sin(0) = Ry/Rx. Participants are trying to clarify the problem context and the correct interpretation of the variables involved.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning whether the equation should indeed be Sin(0) or if it was meant to be Sin(θ). There are discussions about the implications of both interpretations, particularly regarding the values of Ry and Rx. Some suggest using inverse functions to explore the relationships further.

Discussion Status

There is an ongoing exploration of the problem, with some participants providing guidance on how to manipulate the equation based on their interpretations. The clarification that the original equation likely contains θ instead of 0 has been acknowledged, which may help direct the discussion towards a more accurate understanding of the problem.

Contextual Notes

Participants note the potential confusion stemming from the original equation and the importance of correctly identifying the variable represented by 0. There is an indication that the teacher has confirmed this correction.

niknak98
Messages
2
Reaction score
0
Teacher assigned this on first day due tomorrow and i have no clue on some like this one:

Sin 0=Ry/Rx a.) solve for Ry
b.) solve for Rx
c.) solve for 0

?
 
Physics news on Phys.org
Is there anymore information you can provide? Is that actually Sin(0)? Did you attempt to solve it on your own? Have you tried the inverse function?

Anyway, if it really is 0 then it should be obvious. Ry would have to be zero. Rx is then any real which is not equal to zero. Rewriting the equation as arcsin(Ry/Rx) = 0 will demonstrate this as well. I'm saying this because part of me doesn't believe that is really supposed to be sin(0), instead it's probably theta.
 
Last edited:
I can make absolutely no sense out of "solve for 0"! That would be like saying "solve for 2".

I strongly suspect that was supposed to be [itex]sin(\theta)= R_y/R_x[/itex] and your teacher (or you!) missed the horizontal line on the [itex]\theta[/itex].

To "solve for y", multiply both sides by [itex]R_x[/itex]. To "solve for x" one method is to first invert both sides, getting [itex]1/sin(\theta)= R_x/R_y[/itex] and then multiply both sides by [itex]R_y[/itex]. To "solve for [itex]\theta[/itex]" take the inverse sin (arcos or [itex]sin^{-1}[/itex]) of both sides.
 
HallsofIvy said:
I can make absolutely no sense out of "solve for 0"! That would be like saying "solve for 2".

I strongly suspect that was supposed to be [itex]sin(\theta)= R_y/R_x[/itex] and your teacher (or you!) missed the horizontal line on the [itex]\theta[/itex].

To "solve for y", multiply both sides by [itex]R_x[/itex]. To "solve for x" one method is to first invert both sides, getting [itex]1/sin(\theta)= R_x/R_y[/itex] and then multiply both sides by [itex]R_y[/itex]. To "solve for [itex]\theta[/itex]" take the inverse sin (arcos or [itex]sin^{-1}[/itex]) of both sides.

Thanks this really helped and he did correct it that the 0 was theta
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
Replies
14
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
5
Views
3K
  • · Replies 46 ·
2
Replies
46
Views
7K
  • · Replies 6 ·
Replies
6
Views
3K