What is the solution of this differential equation?

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Esmaeil
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how can we solve this differential equation?
(ax+y)∂f/∂x + (ay+x)∂f/∂y =0 with this condition: if a=0 then f(x,y)=x^2 - y^2
 
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Esmaeil said:
how can we solve this differential equation?
(ax+y)∂f/∂x + (ay+x)∂f/∂y =0 with this condition: if a=0 then f(x,y)=x^2 - y^2
[tex]df=\frac{∂f}{∂x}dx+\frac{∂f}{∂y}dy[/tex]

At constant f, [tex]\frac{∂f}{∂x}dx+\frac{∂f}{∂y}dy=0[/tex]

Or equivalently, [tex]\left(\frac{∂y}{∂x}\right)_f=-\frac{(∂f/∂x)}{(∂f/∂y)}[/tex]

Chet
 
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The change of variables (in attachement) leads to a very simple PDE :
 

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