What is the solution of this differential equation?

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SUMMARY

The differential equation (ax+y)∂f/∂x + (ay+x)∂f/∂y = 0 can be solved using a change of variables, particularly when a=0, leading to the solution f(x,y) = x^2 - y^2. The method involves recognizing that at constant f, the total differential df can be expressed as df = (∂f/∂x)dx + (∂f/∂y)dy, which simplifies the equation. The transformation allows for a straightforward approach to solving the partial differential equation (PDE).

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Esmaeil
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how can we solve this differential equation?
(ax+y)∂f/∂x + (ay+x)∂f/∂y =0 with this condition: if a=0 then f(x,y)=x^2 - y^2
 
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Esmaeil said:
how can we solve this differential equation?
(ax+y)∂f/∂x + (ay+x)∂f/∂y =0 with this condition: if a=0 then f(x,y)=x^2 - y^2
df=\frac{∂f}{∂x}dx+\frac{∂f}{∂y}dy

At constant f, \frac{∂f}{∂x}dx+\frac{∂f}{∂y}dy=0

Or equivalently, \left(\frac{∂y}{∂x}\right)_f=-\frac{(∂f/∂x)}{(∂f/∂y)}

Chet
 
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The change of variables (in attachement) leads to a very simple PDE :
 

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