What is the solution of x^2=ln(x)

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Discussion Overview

The discussion revolves around the equation x^2 = ln(x), specifically seeking solutions for both real and complex values of x. Participants explore the nature of the solutions and methods for obtaining them, including graphical analysis and numerical solving techniques.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant asserts that there is no real solution to the equation, arguing that for real numbers x >= 1, the derivative of x^2 exceeds that of ln(x), suggesting no intersection point exists.
  • Another participant suggests plotting both sides of the equation to visually confirm that the curves do not intersect.
  • A participant clarifies their interest in complex solutions, noting that the complex logarithm is multi-valued and suggesting the use of polar form for analysis.
  • There are mentions of using numerical solvers to find solutions, with references to WolframAlpha providing potential answers.
  • Several participants express a casual attitude towards finding solutions, indicating a preference for computational tools over manual calculations.

Areas of Agreement / Disagreement

Participants generally agree that there is no real solution to the equation. However, there is no consensus on the existence or nature of complex solutions, as the discussion includes various approaches and methods without a definitive conclusion.

Contextual Notes

The discussion highlights the need to define the complex logarithm and the implications of its multi-valued nature when seeking complex solutions. There are also references to numerical methods, but specific steps or assumptions in these methods are not detailed.

karpmage
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I was just wondering whether anyone could tell me what's the solution of x^2=ln(x).

This isn't a homework question, I need to know the solution of this equation however for some of the maths that I do in my free time.

Also, I'd be interested to see how the solution is obtained.

Thanks.
 
Last edited:
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Hey karpmage.

In this case there is no solution.

Consider the following argument.

If x is a real number then x >= 1 since ln(1) = 0.

However the derivative of x^2 is 2x and this is less than the derivative of ln(x) which is 1/x.

2x > 1/x for all x >= 1 and since 1^2 > ln(1) = 0, you will never have a point of intersection for the relationship x^2 = ln(x).

So as long as x is a real number, no solution exists.
 
When you have a simple equation like that, you can also plot both sides and realize that the two curves can never cross.
 
I should've mentioned this, I'm sorry, I'm looking for a complex solution to this problem. I was already aware that there wasn't a real solution for x.
 
karpmage said:
I should've mentioned this, I'm sorry, I'm looking for a complex solution to this problem. I was already aware that there wasn't a real solution for x.

In which case you should define what ln x means, since the complex logarithm is multi-valued. Let's say you mean the principal value.

Let x = a + bi. Then perform the necessary operations on each side of the equation (easier when x is expressed in polar (exponential) form for the RHS), equate real and imaginary parts to get simultaneous equations. Plug that into a numerical solver and see if you get any real solutions for a and b.
 
Curious3141 said:
...or you can do that, and just plug the original equation into a numerical solver. :biggrin:

Yeah, I'm getting lazy :blushing:
 
DrClaude said:
Yeah, I'm getting lazy :blushing:

Mathspeak for "lazy" is "elegant". :smile:
 

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