What is the solution to the equation y''' + 4y'' + 4y'=0?

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SUMMARY

The equation y''' + 4y'' + 4y' = 0 is a third-order linear ordinary differential equation (ODE). The characteristic equation derived from this ODE is r^3 + 4r^2 + 4r = 0. This characteristic equation can be factored to find the roots, which leads to the general solution of the ODE. The discussion confirms that applying methods for second-order ODEs can yield valid solutions for this third-order equation.

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RadiationX
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what method do i employ to solve this?

y''' + 4y'' + 4y'=0

does the above lead to something like this?

r^3 +4r^2 +4r=0
 
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Approaching this problem like if it was a 2nd order ODE yield a solution that satisfied the ODE. But I am not sure if this will work all the time.
 
dextercioby said:
Yes,it does.

Daniel.


thx i thought that it did
 

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