What Is the Sound Intensity Ratio Between a Rock Concert and a Jazz Fest?

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Homework Help Overview

The discussion revolves around calculating the sound intensity ratio between a rock concert and a jazz fest, given their sound intensity levels in decibels (dB).

Discussion Character

  • Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of the formula for sound intensity levels and express uncertainty about manipulating logarithmic equations to find the intensity ratio.

Discussion Status

Some participants have provided algebraic approaches to isolate the intensities, while others have acknowledged their own misunderstandings regarding the use of antilogs. The conversation reflects a collaborative effort to clarify the steps needed to solve the problem.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the extent of guidance provided.

tbontom
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[SOLVED] Sound Intensity Level Ratio

Homework Statement



The sound intensity level at a rock concert is 110 dB, while that at a jazz fest is 100 dB. Determine the ratio of the sound intensity at the rock concert to that at the jazz fest.


Homework Equations


B=(10dB) log(I/Io)

The Attempt at a Solution



110=(10db) log (I/1.0*10^-12)
100=(10db) log (I/1.0*10^-12)

dont know where to go from here
 
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Ok, well let I_0=10^-12, then you have two expressions (taking log base 10)

110=10\log\left(\frac{I_1}{I_0}\right) \hskip1cm 100=10\log\left(\frac{I_2}{I_0}\right) and you want to find the ratio \frac{I_1}{I_2}. So, you need to perform some algebra on these expressions to make I_1 and I_2 the subject of the equations, respectively. Try dividing both sides of each equation by 10. After that you will need to take the inverse log of each side: how would you do this?
 
That was my problem, I forgot you could do antilogs. thanks you so much
 
tbontom said:
That was my problem, I forgot you could do antilogs. thanks you so much

No problem!
 

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