What is the Speed of a Ball at its Highest Point Using Conservation of Energy?

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SUMMARY

The speed of a 0.40 kg ball thrown at 9 m/s and an angle of 29° at its highest point can be determined using the conservation of energy principle. At the highest point, the kinetic energy is converted into potential energy, leading to a speed of 0 m/s at that point. The relevant equation is the work of non-conservative forces equals the change in kinetic energy plus the change in potential energy. The correct application of this equation confirms the ball's speed at its apex is zero.

PREREQUISITES
  • Understanding of conservation of energy principles
  • Familiarity with kinetic and potential energy equations
  • Basic knowledge of projectile motion
  • Ability to perform calculations involving gravitational acceleration (9.8 m/s²)
NEXT STEPS
  • Study the conservation of energy in more complex systems
  • Learn about projectile motion and its equations
  • Explore the concept of maximum height in projectile motion
  • Investigate the effects of air resistance on projectile trajectories
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of energy conservation in projectile motion.

Bones
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Homework Statement


0.40 kg ball is thrown with a speed of 9 m/s at an upward angle of 29°.
(a) What is its speed at its highest point? (Use conservation of energy.)


Homework Equations


Work of non conservative forces = change in KE + change in PE


The Attempt at a Solution


I am not sure how to go about this.
 
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Is this equation correct? 0=-1/2(0.40kg)(v^2)+(-(0.40kg)(9.8m/s^2)h
 
I figured it out ;)
 

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