ovicenzu
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TSny said:I'm not sure what you're getting at here. Can you expound on this?
Does the differential, dP, simplify if we look at the the change from P(0) to P(0+dt)?
The discussion centers on calculating the speed of a freight car when all the sand has been released. The key equation derived is \( v = \frac{Fm}{M\lambda} \), where \( F \) is the applied force, \( m \) is the initial mass of sand, \( M \) is the mass of the freight car, and \( \lambda \) is the rate of sand flow. Participants clarify the momentum conservation approach, emphasizing the need to account for the momentum of sand falling out and the changing mass of the system. The final expression for the change in momentum leads to the differential equation \( (M+m-\lambda t)\frac{dv}{dt} = F \).
PREREQUISITESPhysics students, educators teaching dynamics, and engineers dealing with systems involving variable mass, such as rockets or freight transport systems.
TSny said:I'm not sure what you're getting at here. Can you expound on this?
Yes. What do you get for dP from P(0) to P(0+dt)? How would you use this to solve the problem?ovicenzu said:Does the differential, dP, simplify we look at the the change from P(0) to P(0+dt)?
TSny said:Yes. What do you get for dP from P(0) to P(0+dt)? How would you use this to solve the problem?