What is the Speed of a Particle with Total Energy 3 Times its Rest Energy?

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Homework Help Overview

The problem involves finding the speed of a particle whose total energy is three times its rest energy, situated within the context of relativistic mechanics.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to relate total energy and kinetic energy using the equation KE = γmc² - mc², questioning whether to set total energy as 3mc² or to directly use γmc² = 3mc². Other participants discuss the connection between the equations and suggest alternative approaches to find the speed.

Discussion Status

Participants are exploring different interpretations of the equations involved. Some guidance has been offered regarding the use of the relativistic factor γ, but there is no explicit consensus on the correct approach yet.

Contextual Notes

There is a mention of a potential misunderstanding related to the English language, indicating that communication may be affecting the clarity of the discussion.

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Homework Statement


Find the speed of a particle whose total energy is 3 times its rest energy.

Homework Equations


[tex]KE = \gamma mc^2 - mc^2[/tex]

The Attempt at a Solution


i let total energy = 3mc^2 and then :

[tex]\gamma mc^2 = KE + mc^2[/tex]
[tex]3mc^2 = KE + mc^2[/tex]
[tex]v = \frac{\sqrt{3}}{2} c[/tex]

Is this correct? or should i let [tex]\gamma mc^2 = 3mc^2[/tex] and work it out immediately?

Any help will be appreciated.
 
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[tex]3mc^2 = KE + mc^2[/tex] is correct, but I don't see how is this connected to [tex]v = \frac{\sqrt{3}}{2} c[/tex], So I can't point out which part you did it wrong...
or should i let [tex]\gamma mc^2 = 3mc^2[/tex] and work it out immediately?
yes
 
Use 1/sqrt{1-v^2/c^2}=3,and solve for v.
 
yeah, got it thanks, English problem. bah. :P
 

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