What is the speed of sound at this temperature?

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The speed of sound in air is calculated using the formula that relates it to the square root of temperature in Kelvin. At 288 K, the speed of sound is 340 m/s, which increases to 346 m/s at 298 K. This results in a percent change of approximately 1.76%. The calculations appear to be correct based on the provided formulas. The discussion confirms the accuracy of the answers given.
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Homework Statement



The speed of sound in air is proportional to the square root of the temperature in kelvin. A flute player begins playing with the temperature of air in the tube at 288 K. The speed of sound at this temperature is 340 m s–1. After a few minutes playing the air temperature in the bore rises to 298 K.

What is the speed of sound at this temperature?
What is the percent change in the value of the speed of sound?2. The attempt at a solution

\frac{340}\sqrt{288} = \frac{V}\sqrt{298}

V @298K = 346 m s–1
% change = 1.76%

Can someone please check if both my answers are correct? Thanks!
 
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I don't see any problem.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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