- #1

Kolika28

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**Summary::**Two speakers A and B are at rest, and a listener L stays on the line that connects the two speakers (see picture). The speakers have almost the same frequency. Assume that the speed of sound in air is 340 m/s. When the listener is at rest, he/she hears beats with frequency 6 Hz. The listener is moving towards speaker B with a constant speed of 5 m/s, he/she hears no beat (same frequency from both speakers).

a) What is the frequency of speaker A?

Now the listener is at rest, but the speaker B moves at a constant speed in the same direction that connects A and L. Speed is positive to the right (see the figure), otherwise it is negative.

b) What is the speed of the sound source B (m/s) so that the listener does not hear beats?

a) So ##f_beat=abs(f_A-f_B)=6##. Since the listener does not here at beat when moving toward B ##f_A=f_B## here. Then I use the formula for doppler effect:

##f_L=\frac{340 m/s -5 m/s}{340 m/s}*f_A## (1) and ##f_L=\frac{340 m/s+5 m/s}{340}*f_B## (2). I use the fact that ##f_B=f_A-6## and set the equations 1 and 2 equal each other and get that ##f_A=207 Hz##.

b) I don't get the right answer for this problem. I do almost the same like I did in a) :

##f_L=\frac{340 m/s+0}{340 m/s+0}*207 Hz## and ##f_L=\frac{340 m/s+0}{340 m/s +v_B}*(207-6)Hz## and I get that ##v_B=9.8 m/s##. But this is not correct according to my teacher. Does anyone have some tips?