What Is the Speed of the Ball When Kicked Back in This Soccer Scenario?

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SUMMARY

In the soccer scenario, Jack kicks a ball to John at a velocity of 5.40 m/s, and the total time for the ball to return to Jack is 2.6 seconds. The distance between them is 6 meters, leading to a calculated time of 1.11 seconds for the ball to reach John. The speed of the ball when kicked back to Jack remains 5.40 m/s, as there is no deceleration during its travel. The calculations confirm that the speed of the ball does not change when it is kicked back.

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Homework Statement


Jack and John are standing 6m apart from each other playing soccer. Jack kicks the ball to John and John kicks it back immediately. Jack kicked the ball with a velocity of 5.40 m/s and after 2.6 s he got the ball back. Suppose there's no deceleration of the ball when it's moving and that we can neglect the time for John to kick the ball. What is the speed of the ball when it's kicked back to Jack?


Homework Equations



V= D/T

The Attempt at a Solution


5.4 m/s = 6 /t = 1.11 seconds
1.11 + 2.6 = 3.71 seconds total
3.71 = ( (6/5.4) + (6/v) ) = 2.3

I'm doing something wrong, because I'm not getting the right answer.
thanks in advance
 
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OUstudent said:
5.4 m/s = 6 /t = 1.11 seconds
1.11 + 2.6 = 3.71 seconds total
1.11 is the time it takes for the ball to reach John. 2.6 is the total time.
 
I'm an idiot...

Thanks
 

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