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Find the sum to infinity of the series $1 +2z +3z^2+4z^3+...$
The sum to infinity of the series \(1 + 2z + 3z^2 + 4z^3 + \ldots\) can be derived using calculus techniques. By integrating the series and then differentiating the resulting function, the closed form of the sum is established as \(\frac{1}{(1-z)^2}\) for \(|z| < 1\). This approach leverages the properties of power series and their convergence criteria.
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