What is the tension force in a tug-of-war between two teams?

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In a tug-of-war, each team consists of five members pulling with an average force of 500 N. The tension in the center of the rope is 2500 N, as it reflects the force exerted by one team against the opposing team. Although the total force exerted by both teams is 5000 N, the tension at the center remains constant at 2500 N due to Newton's Third Law. The rope transmits this force equally to both teams, maintaining equilibrium. Thus, the tension is the same throughout the rope, confirming that 5000 N is not the correct answer.
gcombina
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19. In a tug-of-war, each man on a 5-man team pulls with an average force of 500 N. What is the tension in the center of the rope?
(a) zero Newtons (c) 500 N (e) 5000 N
(b) 100 N (d) 2500 N

My answer was 2500 N as that is teh force pulling the rope, why the answer is 5000? are we talking about a 5-man team on EACH side?/

Thanks!
 
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gcombina said:
19. In a tug-of-war, each man on a 5-man team pulls with an average force of 500 N. What is the tension in the center of the rope?
(a) zero Newtons (c) 500 N (e) 5000 N
(b) 100 N (d) 2500 N

My answer was 2500 N as that is teh force pulling the rope, why the answer is 5000? are we talking about a 5-man team on EACH side?/

Thanks!
Yes, there is a team on each side (otherwise there would be no tension, they would all fall :-) )
 
Yes, two teams. Not much fun without an opposing team!
 
gcombina said:
19. In a tug-of-war, each man on a 5-man team pulls with an average force of 500 N. What is the tension in the center of the rope?
(a) zero Newtons (c) 500 N (e) 5000 N
(b) 100 N (d) 2500 N

My answer was 2500 N as that is teh force pulling the rope, why the answer is 5000? are we talking about a 5-man team on EACH side?/

Thanks!
Assuming that there is negligible acceleration, and that the center of the rope is somewhere between the two teams, then Newton's Third Law says you're correct, the center of the rope is exerting a force of 2500 N on the team in question. (Of course, the opposing team would be exerting a force opposite that of the 5 man team with a magnitude very close to 2500 N. The center of the rope also exerts a force of 2500 N on that opposing team as well, but those don't sum to be 5000 total.) This simply how Tension in a rope is expressed.

Your answer is correct.
 
gcombina said:
19. In a tug-of-war, each man on a 5-man team pulls with an average force of 500 N. What is the tension in the center of the rope?
(a) zero Newtons (c) 500 N (e) 5000 N
(b) 100 N (d) 2500 N

My answer was 2500 N as that is teh force pulling the rope, why the answer is 5000? are we talking about a 5-man team on EACH side?/

Thanks!

There are people pulling the rope at both sides, but your answer is correct. The tension is the same all along the rope. Pulling the rope with the same force (2500 N) at both ends, the rope and people are in rest as the net force on the rope is zero. The five people at the right end pull the rope with 2500 N to the right and the rope pulls the people back with its tension, which should be 2500 N. The tension is the same everywhere in the rope: it pulls the people at the other end with the same force, to the right, so those people have to pull with 2500 N force to the left. No way to get 5000 N for the tension.
 
ehild said:
. The tension is the same all along the rope.
Not in any of the team tug-o-wars I've seen!
 
NascentOxygen said:
Not in any of the team tug-o-wars I've seen!

It is the same all along the portion that is between the two teams.
 

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