What is the tension in the rope holding a helium-filled balloon at a party?

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Homework Help Overview

The problem involves calculating the tension in a rope holding a helium-filled balloon. The balloon has a specified mass and dimensions, and the density of helium is provided. Participants are exploring the forces acting on the balloon, including buoyant force and gravitational force.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between buoyant force, tension, and the weight of the balloon. There are attempts to apply the formula for buoyant force and clarify the volume of the balloon. Questions arise regarding the density of the displaced fluid and the total mass of the balloon and helium.

Discussion Status

The discussion is active, with participants questioning assumptions about the volume and density involved in the calculations. Some guidance has been offered regarding the correct density of the displaced fluid and the total mass, but no consensus has been reached on the final calculations.

Contextual Notes

Participants are working within the constraints of the problem as presented, including the specific values for mass and density. There is an acknowledgment of potential errors in volume calculations and the implications for the final answer.

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Homework Statement



Bozo the clown brings an empty birthday balloon with a mass of 0.0120 kg to your party. Bozo fills the balloon with helium of density 0.181 kg/m3. The filled balloon is a perfect sphere with a radius of 0.500 m. Bozo ties the balloon to a rope and holds is so that it is vertical. What is the tension in the rope?

Homework Equations


Ft= tension force
Fb=buoyant force
π=pi
4πr^3=volume of sphere

The Attempt at a Solution



i tried Fnet=0 = Fb-Ft-mg

Ft=Fb-mg=(densityfluid)(Vdisplaced)(g) - (m)(g)

[(4π(.5)^3)(9.8)] - [(.012)(9.8)] ==> Ft=2.6687 N which is obviously not correct, as I'm asking this question.

Any good help is greatly appreciated!

-aea
 
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awertag said:
4πr^3=volume of sphere
Double check this formula.

The Attempt at a Solution



i tried Fnet=0 = Fb-Ft-mg
That's good.

Ft=Fb-mg=(densityfluid)(Vdisplaced)(g) - (m)(g)

[(4π(.5)^3)(9.8)] - [(.012)(9.8)] ==> Ft=2.6687 N which is obviously not correct, as I'm asking this question.
What's the density of the displaced fluid? What's the total mass of the balloon plus its contents?
 
well the density is given = .181 kg/m^3. But I see what you're saying: the total mass is .012 PLUS the mass of helium...so I would find that with density (.181) times volume (1.5708) so mass total equals .2963 kg?
 
awertag said:
well the density is given = .181 kg/m^3.
That's the density of the helium. But the buoyant force equals the weight of the displaced fluid. What's the density of the displaced fluid?

But I see what you're saying: the total mass is .012 PLUS the mass of helium...so I would find that with density (.181) times volume (1.5708) so mass total equals .2963 kg?
Right idea, but wrong volume.
 
oHH okay so the density of air which is 1.29 kg/m^3.
But why is the volume wrong?
 
oh gosh never mind, i see the volume is 4/3 pi r cubed haha :) thanks ill try it now
 
But now i get a final answer with a negative force, so that can't be right...
 
Ok I've finally gotten it! Thank you so much. Have a great day :)
 

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