What is the Terminal Velocity of a Skydiver with Given Parameters?

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Homework Help Overview

The discussion revolves around calculating the terminal velocity of a skydiver using given parameters, specifically focusing on the relationship between drag force and gravitational force. The subject area includes concepts from physics related to forces, motion, and fluid dynamics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the equation for terminal velocity and the relationship between drag force and weight. There is an attempt to derive the formula for velocity based on the provided parameters. Questions arise regarding unit conversions and the validity of the calculated velocity.

Discussion Status

The discussion is ongoing, with some participants providing guidance on the approach to take. There is recognition of potential issues with unit conversions that may affect the outcome, but no consensus has been reached on the final value of terminal velocity.

Contextual Notes

Participants are addressing the need to convert the area from cm² to m², which may impact the calculations. There is also mention of the original poster's confusion and the time spent on the problem, indicating a struggle with the concepts involved.

newbe318
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Homework Statement


I attached a screen shot of the problem.
Screen Shot 2015-10-14 at 9.40.16 PM.png


Homework Equations


D= 1/2 C p A v^2
bv=mg

The Attempt at a Solution


I spent 3 long hours on this problem. I confused myself even more. Please help me understand what is going on.
 
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Please show your best attempt with reasoning.
 
I know that at terminal velocity, bv=mg ... so, mg=1/2CpAv^2.. would I just solve for v? .. v=sqrt((2mg)/(CpA))... v=1.38m/s ?
m: 84kg
C: 0.8
p: 1.2kgm^3
A: 987cm^2
 
newbe318 said:
I know that at terminal velocity, bv=mg ... so, mg=1/2CpAv^2.. would I just solve for v? .. v=sqrt((2mg)/(CpA))... v=1.38m/s ?
m: 84kg
C: 0.8
p: 1.2kgm^3
A: 987cm^2
That's the right approach, but I don't understand how you get such a small velocity. Did you forget to convert the area to m2?
 

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