What is the Thickness of the Upper Layer?

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hopelesss
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My task is

Let's consider a model made up of two horizontal layers: the upper layer has a velocity
Vp1=3.0 km/s and the lower layer (or half space) has a velocity Vp2= 5.0 km/s. Aseismic experiment is conducted at the surface and showsthat the P wave refracted in the lower layer has a critical distance of 7.5 km and a critical time of 4.17 s. Based on this information, what is the thickness of the upper layer?

1. can i solve this by useing ti= (2z(v2^2 -v1^2)^1/2) / (v1*v2) and then
z= (ti*v1*v2) / 2(v2^2-v1^2)^1/2?
2. Is critical distance the thickness of layer 2?

greatful for any help
 
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1. can i solve this by useing ti= (2z(v2^2 -v1^2)^1/2) / (v1*v2) and then
z= (ti*v1*v2) / 2(v2^2-v1^2)^1/2?
Check where the formula comes from, that should answer the question.
Where did the critical distance go there?

2. Is critical distance the thickness of layer 2?
No.
 
It only say ''two-layer case with horizontal interface'' and the intercept time is given by ... and solving for refractor depth. And i can't find any equation with xcrit in it. tryed to google it but did not find any equation with Xcrit in it.
 
Searching for "critical distance seismics" gives the Wikipedia article about seismic refraction as one of the first hits, and this article has a formula. I think it is hard to miss that.
 
I only find seismic refraction when i google that.
I still don't get it. i would still miss the T0 if i use that equation. And the critical distance and critical time info would not have been used
 
can i do this
ic= sin^-1 3/5 = 36,8
tan 36,8 = (7,5/2)/b = 0,75*3,75 = 2,8
And say upper layer is 2,8meters?
 
Meters? Certainly not.

I don't understand what you calculated there (please add a sketch), in particular I don't see how this is supposed to include the path of the waves at the critical distance.
 
confused, taskes says ''Based on this information, what is the thickness of the upper layer?''