What is the Time Equation for Constant Acceleration?

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SUMMARY

The discussion focuses on deriving the time equation for constant acceleration, specifically using initial velocity, distance, and acceleration. The kinematic equation discussed is s = v0t + 1/2at², which requires solving a quadratic equation to isolate time (t). Participants confirmed that the acceleration is constant and provided guidance on using the quadratic formula to find the solution. Ashley's simulation results for distances of 25 and 50 meters with an initial velocity of 2.00 m/s and acceleration of 2.00 m/s² were 4.099 seconds and 6.141 seconds, respectively.

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This discussion is beneficial for students new to physics, particularly those studying kinematics, as well as educators and anyone interested in understanding the relationship between time, distance, and acceleration in motion.

kriegera
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Hi All - I am trying to find an equation that gives the time as a function of initial velocity, distance traveled, and specified acceleration. That is, t = some function of v(0), d, and a.

We ran a simulation problem for distances 25 and 50 meters and my times were - 4.099 and 6.141 respectively for initial velocity of 2.00 and inital acceleration of 2.00. i can't come up with any equations that fit my data. any input please?

Thank you!
Ashley
 
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So would it be:
t=SQRT(2s-v(o)/a

s=distance
v(o)=inital velocity

I've tried this but it doesn't give me the exact anser - is it ok to round up or down? Initally I found final velocity and then plugged it in but the challenge is to use one equation. Input?

Thank you!
 
kriegera said:
So would it be:
t=SQRT(2s-v(o)/a
The starting equation would be:
s = v0t + 1/2at2

To find t you'll need to solve the quadratic.
 
Doc Al said:
The starting equation would be:
s = v0t + 1/2at2

To find t you'll need to solve the quadratic.

Thank you for this tip. I am not very "up" on my physics - this is my first introduction to it on a college level. What are the rules for solving for the quadratic? Does that involve derivitives? Thank you!
 
kriegera said:
What are the rules for solving for the quadratic? Does that involve derivitives?
No need for calculus, just the 'quadratic formula'. (Google it!)

Note that I am assuming that your setup is one where the acceleration is constant. (You didn't actually state that.)
 
Note that I am assuming that your setup is one where the acceleration is constant. (You didn't actually state that.)[/QUOTE said:
Yes - acceleration is constant. I'll let you know what I find out. Thanks.
 

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