What is the total time in the air for the parachutist's jump?

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SUMMARY

The total time in the air for a parachutist's jump can be calculated by analyzing two phases: free fall and deceleration. The parachutist falls 53.2 meters before opening the parachute, during which time he accelerates due to gravity (g = 9.81 m/s²). After the parachute opens, he decelerates at 2.00 m/s² until reaching a final speed of 3.23 m/s upon landing. By applying kinematic equations, the total time in the air is determined by summing the time of free fall and the time of deceleration.

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  • Understanding of kinematic equations for uniformly accelerated motion
  • Knowledge of gravitational acceleration (g = 9.81 m/s²)
  • Ability to calculate time, distance, and velocity in physics
  • Familiarity with deceleration and its effects on motion
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  • Study kinematic equations in detail, focusing on free fall scenarios
  • Learn how to calculate time of flight for objects under constant acceleration
  • Explore the effects of deceleration on motion and how to apply it in real-world problems
  • Investigate practical applications of physics in parachuting and skydiving
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Physics students, educators, and anyone interested in understanding the dynamics of free fall and deceleration in parachuting scenarios.

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Hey could someone explain to me this problem because i tried every single variation of the rules i learned in class, v = delta d/ delta t a= delta v/ delta t ect.. and i kept getting the wrong answer.

A parachustist jumps from an airplane and freely falls y=53.2 m before opening his parachute. Thereafter, he decelerates at a=2.00 m/s2. As he reaches the ground, his speed is 3.23 m/s. How long was the parachutist in the air?
 
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First step - free fall - requires you to find time needed to cover distance while accelerating at g. Second step - slowing down - requires you to find time necessary to slow down from the final speed of free fall (you will have to calculate it from time and g) to the landing speed.
 

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