Ok, to clear the problems with whether time is a dimension or not i guess we would have to re-state the definition of various terms and how each term relate to each other.
Vetors
a) Vector is a quantity that has both a
magnitude and
direction.
b) When representating a vector on a coordinate system, the tail of the vector can be positioned on top of any point of the coordinate system; which makes the vector
independent from a specific location or
independent of any point of reference.
c) There are vector operations that allow us to
re-shape,
shift,
rotate and
transform vectors.
Dimensions
-Mathematical definition of dimensions:
a) Dimensions are
special vectors where these vectors will become part of number lines for a new coordinate system.
b) The relation of each vectorial space
may and may not be of an orthogonal basis.
-Scientific definition of dimensions:
a) For the purpose of calculations, it has the same as the mathematical meaning except;
b) a dimension (in science) must be a
fundamental quantity and because of its importance it is given a
fundamental unit for the purpose of
dimensional analysis.
Fundamental Unit and Quantity
Is an important quantity which can be measured and which other units will be based on. For example, force is made of the fundamental quantities of mass, time and length.
Dimensional Analysis
Is a way to make sure that a calculation is done correctly and that the computation done does not mix different units improperly.
Time
a) Time is a measuring system used to sequence events, to compare the durations of events and the intervals between them.
b) Time is a fundamental quantity and bears the fundamental units of
seconds.
Proper Time thanks to DaleSpam for clarifying
Is the time elapsed by a moving or accelerating observer.
The way proper time is measured is the follows:
-From the relation between proper time and time of the outside observer in spacetime:
\Delta t = \frac{\Delta t_p}{\sqrt {1 - \frac {(\Delta x)^2 + (\Delta y)^2 + (\Delta z)^2 }{c}}}
-Solve for proper time and in a continuous curve, \Delta is replaced with d.
dt_p = \sqrt {{1 - \frac {(dx)^2 + (dy)^2 + (dz)^2}{c}} dt
-Integrate both sides:
t_p = \int_D \sqrt {1 - \frac{(dx)^2 + (dy)^2 + (dz)^2}{c}} dt
Which is the line integral of a path or curve D.
@Passionflower
-First, proper time only defines the time of a moving or accelerating observer.
-To define the time for a an observer that it not accelerating, you would still have to transform the proper time so that you get the time for the non-accelerating observer.
-Proper time is the total amount of time elapsed by someone who is accelerating. Meaning it is scalar and not the measuring system as i defined time.
-What are the units of the proper time? It is still seconds. And applying dimensional analysis i still get that the proper time is just a point or group of points or value of the dimensional system of time.
-Proper time does not say anything about time not being a dimension; it is just saying that an accelerating observer is experiencing a different rate of time flow.
@TheAlkemist
TheAlkemist said:
So if time is a fundamental QUANTITY of matter, what is the time of a brick?
Fundamental quantity does not refer to matter but to the real world in general. The real world is not only composed of matter but also space which in our case we use length. It is also composed of matter which is why we use mass. It is also composed of sequence of events which is why we use time.
Let's say this, if fundamental quantity only refers to matter then length can't be a fundamental quantity. Just because you are specifying what is the volume you don't necessarily specify its mass because it could have variable density.
Please TheAlkemist, read about fundamental quantities and dimensional analysis.