What is the uncertainty in a squared quantity?

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Homework Help Overview

The discussion revolves around calculating the uncertainty in a squared quantity, specifically focusing on the expression D^2 derived from a measurement D with an associated uncertainty. The subject area includes uncertainty analysis in physics, particularly in the context of measurements and their propagation through mathematical operations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore different methods for calculating uncertainty, including the power rule and multiplication rule. Questions arise regarding the correctness of formulas used and the discrepancies between calculated uncertainties.

Discussion Status

Some participants have offered alternative formulas and approaches for calculating uncertainty, leading to a discussion about the accuracy of different methods. There is recognition of potential errors in the original poster's calculations, and some participants express understanding of the corrections provided.

Contextual Notes

Participants are working within the constraints of homework rules, which may limit the information they can share or the methods they can use. There is a noted confusion regarding the application of uncertainty formulas, particularly in the context of squaring a measurement.

lemin_rew
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Homework Statement



D= A +/-ΔA
D= 5.160 +/- 0.01 cm

D^2= 26.6 +/- 0.1 cm^2

Homework Equations



for the power rule uncertainty
:
A ((ΔA/A) + (ΔA/A) )
So then its (5.160)( (0.01/5.16)(2)) = 0.004

The Attempt at a Solution


im getting 0.004 as the absolute uncertainty but the uncertainty calculator i found online gives me 0.1 .
is my formula wrong?
 
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For the uncertainty as a result of a power in general, let Q = xn and δx be the uncertainty in x. Then
$$\frac{\delta Q}{|Q|} = |n| \frac{\delta x}{|x|}$$
In your case the power is n = 2 and x is a positive value, so that δQ becomes:
$$\delta Q = 2 x^2 \frac{\delta x}{x} = 2 x \delta x$$
Your formula A ((ΔA/A) + (ΔA/A) ) should have been A2 ((ΔA/A) + (ΔA/A) ).
 
gneill said:
For the uncertainty as a result of a power in general, let Q = xn and δx be the uncertainty in x. Then
$$\frac{\delta Q}{|Q|} = |n| \frac{\delta x}{|x|}$$
In your case the power is n = 2 and x is a positive value, so that δQ becomes:
$$\delta Q = 2 x^2 \frac{\delta x}{x} = 2 x \delta x$$
Your formula A ((ΔA/A) + (ΔA/A) ) should have been A2 ((ΔA/A) + (ΔA/A) ).

oh ok. so that is what i did wrong. I got it now. THANK YOU SO MUCH.!
 
To make this problem simple, see D² as D * D.

Well, the rule for finding the uncertainty in multiplication is Δw = √((yΔx)² + (xΔy)²), coming from w = xy. It's the simpler similar version of the formula other user uses.

Now, you try to use that formula.
 
NasuSama said:
To make this problem simple, see D² as D * D.

Well, the rule for finding the uncertainty in multiplication is Δw = √((yΔx)² + (xΔy)²), coming from w = xy. It's the simpler similar version of the formula other user uses.

Now, you try to use that formula.

using this equation, gives me 0.0729, whereas the previous one i used gives me 0.1032.
so, i can conclude that Δw = √((yΔx)² + (xΔy)²) formula gives me more precise uncertainty?
 

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