What is the usage of an osculating plane?

  • Thread starter Thread starter Desikosh
  • Start date Start date
  • Tags Tags
    Plane
Click For Summary
The discussion centers on the concept of the osculating plane, which is the plane that best approximates a given space curve. Its primary application is in determining the osculating circle, which has practical implications, such as guiding the path of a spaceship along a curve. The radius of the osculating circle directly relates to the curvature of the curve, providing a clear geometric interpretation. Resources like Spivak's "A Comprehensive Introduction to Differential Geometry" are recommended for a deeper understanding. The conversation highlights the challenges of seeking clarity in complex topics and the importance of student engagement in learning.
Desikosh
Messages
2
Reaction score
0
so i joined this forum almost 2 weeks ago i was wandering in its vast halls till now and still feel a bit lost,as an student couldn't let myself to get into many things i couldn't understand but i enjoyed this huge amount of knowledge being shared here :)
sorry if that was much off topic now the real question:
so i was listening to professor when she was talking about osculating plane and its equations when i failed to communicate with the topic properly, then i simply asked her "what is the usage of an osculating plane?" she just smiled and said" is there a usage?" ,"yes there MUST be a use for it !" i replied.then another smile and she said"oh great, then you'll find that reason and present it to us next week"..
i looked where ever i could, although i don't know many sources. but i couldn't find the USAGE of osculating plane. now i may not be able to prepare it for presentation but at least I'd appreciate if one of you could lead me somewhere i can find the answer .

thank you :)
 
Physics news on Phys.org
Worst professor ever.. She just tries to avoid that her students ask her perfectly reasonable questions. Seriously, this is awful.

Anyway, the osculating plane is the plane which best approximates the given space curve. One possible application of the osculating plane is to find the "equation" of the osculating circle. The osculating circle has a clear physical interpretation: let's say you travel in a spaceship and your path is the given space curve. So in traveling the space curve, you are given a steering wheel which you turn in different directions. Let's say that at a certain point you just hold your steering wheel fixed, then your path will be described by the osculating circle at that point.

The osculating circle also gives an incredibly neat interpretation of the curvature. Indeed, the radius of the osculating circle at a point ##\alpha(s)## is exactly ##1/\kappa(s)##. In order to prove that (and to find the equation of the osculating circle), it is easiest to work with the osculating plane.

A rather nice treatment is given in Spivak's "A Comprehensive Introduction to Differential Geometry, Vol. 2" (don't worry, you don't need to know Vol. 1 to follow his treatment). See page 24 (it starts right before prop. 10) and you will need the discussion on page 3,4,5,6 too.

See here for an alternative discussion: http://theronhitchman.blogspot.be/2013/02/an-interpretation-of-curvature.html I recommend reading this discussion first. It's well-organized, but not completely rigorous. After that you should look things up in Spivak to make it more rigorous.
 
I would not consider asking students to think for themselves "awful" teaching.
 
HallsofIvy said:
I would not consider asking students to think for themselves "awful" teaching.

It's clear she didn't know the answer. So instead of admitting it and perhaps looking it up herself, she transfers her job to the student.

Well, that this is awful teaching is probably a matter of opinion. So let's just agree to disagree :-p
 
thank you very much that will surely help a lot :)
plus the spaceship thingy was an amazing example !
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 8 ·
Replies
8
Views
752
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 8 ·
Replies
8
Views
572
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 43 ·
2
Replies
43
Views
7K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
13
Views
2K
Replies
1
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K