What is the Value of a Complex Exponential Expression?

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sambarbarian
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Find the value of [itex]\sqrt{-\sqrt{3}+\sqrt{3 + 8 \sqrt{7 + 4\sqrt{3}}}}[/itex]the options are [tex]1[/tex] , [tex]0[/tex] , [tex]2[/tex] , [tex]3[/tex]
 
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sorry , i got so excited using latex for the first time i forgot to give my attempts

take the value as [tex]x[/tex]

square both sides and take [tex]-sqrt{3}[/tex] to the other side , and continue doing till simplified , but this got way complicated than i intended.
 


oh , sorry again , the options are 1 , 0 , 2 and 3
 


sambarbarian said:
oh , sorry again , the options are 1 , 0 , 2 and 3

Start by writing 7+4√3 as 4+4√3+3 which can be simplified to (2+√3)^2.
 


Well just work backwards from the most inner radical and take approximations.

For the answer to be equal to 0, we need to have

[tex]\sqrt{-\sqrt{3}+\sqrt{3}}[/tex]

which we clearly don't. For 1 we need

[tex]\sqrt{-\sqrt{3}+(1+\sqrt{3})}[/tex]

And using the approximation of [itex]\sqrt{3}\approx1.7[/itex] would suffice.

For 2 we need

[tex]\sqrt{-\sqrt{3}+(4+\sqrt{3})}[/tex]

And finally for 3 we need

[tex]\sqrt{-\sqrt{3}+(9+\sqrt{3})}[/tex]

So what is the radical

[tex]\sqrt{3+8\sqrt{7+4\sqrt{3}}}[/tex] closest to? 2.7, 5.7 or 10.7?
 


Mentallic said:
Well just work backwards from the most inner radical and take approximations.

For the answer to be equal to 0, we need to have

[tex]\sqrt{-\sqrt{3}+\sqrt{3}}[/tex]

which we clearly don't. For 1 we need

[tex]\sqrt{-\sqrt{3}+(1+\sqrt{3})}[/tex]

And using the approximation of [itex]\sqrt{3}\approx1.7[/itex] would suffice.

For 2 we need

[tex]\sqrt{-\sqrt{3}+(4+\sqrt{3})}[/tex]

And finally for 3 we need

[tex]\sqrt{-\sqrt{3}+(9+\sqrt{3})}[/tex]

So what is the radical

[tex]\sqrt{3+8\sqrt{7+4\sqrt{3}}}[/tex] closest to? 2.7, 5.7 or 10.7?

Although I find it hard to believe, the original expression actually does come out exactly to a small integer value.

RGV
 


Ray Vickson said:
Although I find it hard to believe, the original expression actually does come out exactly to a small integer value.

RGV

The surds inside surds quickly lose their value! :smile:

What I find even more amazing is infinitely nested surds such as

[tex]\sqrt{10+\sqrt{10+\sqrt{10...}}}=\frac{1+\sqrt{41}}{2}\approx 3.7[/tex]

Which is a lot smaller than you'd initially guess!
 


Pranav-Arora said:
Start by writing 7+4√3 as 4+4√3+3 which can be simplified to (2+√3)^2.

Ingenious Pranav! :cool: And the same method can be applied again to get a small integer as result.

ehild
 


Pranav-Arora said:
Start by writing 7+4√3 as 4+4√3+3 which can be simplified to (2+√3)^2.

ehild said:
Ingenious Pranav! :cool: And the same method can be applied again to get a small integer as result.

ehild
Yes, Pranav-Arora !

I'm glad to see you figured it out before I saw this thread and racked my brain over this. (Of course, then I racked my brain over whether it's racked or wracked .)
 


Thanks ehild and SammyS! :blushing:
 


Awesome solution pranav , can't believe i missed that. i got the answer 2 , thank you. btw which city are you from ?
 
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