What is the Value of a Complex Exponential Expression?

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Homework Help Overview

The discussion revolves around evaluating a complex expression involving nested radicals, specifically the expression \(\sqrt{-\sqrt{3}+\sqrt{3 + 8 \sqrt{7 + 4\sqrt{3}}}}\). Participants are exploring the possible values of this expression, which are given as 1, 0, 2, and 3.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss various methods to simplify the expression, including squaring both sides and approximating values. Some question the clarity of the problem's requirements and the implications of the given options.

Discussion Status

There is an ongoing exploration of different approaches to evaluate the expression, with some participants suggesting simplifications and approximations. While some express skepticism about the outcome being a small integer, others appear to find potential methods leading toward a solution.

Contextual Notes

Participants note the complexity of nested radicals and the challenge of determining the exact value without further context or constraints. The discussion reflects a mix of attempts and insights without reaching a definitive conclusion.

sambarbarian
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Find the value of [itex]\sqrt{-\sqrt{3}+\sqrt{3 + 8 \sqrt{7 + 4\sqrt{3}}}}[/itex]the options are [tex]1[/tex] , [tex]0[/tex] , [tex]2[/tex] , [tex]3[/tex]
 
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sorry , i got so excited using latex for the first time i forgot to give my attempts

take the value as [tex]x[/tex]

square both sides and take [tex]-sqrt{3}[/tex] to the other side , and continue doing till simplified , but this got way complicated than i intended.
 


It's not clear what the problem is asking you to do here. The "value" of the expression is just what is given.
 


oh , sorry again , the options are 1 , 0 , 2 and 3
 


sambarbarian said:
oh , sorry again , the options are 1 , 0 , 2 and 3

Start by writing 7+4√3 as 4+4√3+3 which can be simplified to (2+√3)^2.
 


Well just work backwards from the most inner radical and take approximations.

For the answer to be equal to 0, we need to have

[tex]\sqrt{-\sqrt{3}+\sqrt{3}}[/tex]

which we clearly don't. For 1 we need

[tex]\sqrt{-\sqrt{3}+(1+\sqrt{3})}[/tex]

And using the approximation of [itex]\sqrt{3}\approx1.7[/itex] would suffice.

For 2 we need

[tex]\sqrt{-\sqrt{3}+(4+\sqrt{3})}[/tex]

And finally for 3 we need

[tex]\sqrt{-\sqrt{3}+(9+\sqrt{3})}[/tex]

So what is the radical

[tex]\sqrt{3+8\sqrt{7+4\sqrt{3}}}[/tex] closest to? 2.7, 5.7 or 10.7?
 


Mentallic said:
Well just work backwards from the most inner radical and take approximations.

For the answer to be equal to 0, we need to have

[tex]\sqrt{-\sqrt{3}+\sqrt{3}}[/tex]

which we clearly don't. For 1 we need

[tex]\sqrt{-\sqrt{3}+(1+\sqrt{3})}[/tex]

And using the approximation of [itex]\sqrt{3}\approx1.7[/itex] would suffice.

For 2 we need

[tex]\sqrt{-\sqrt{3}+(4+\sqrt{3})}[/tex]

And finally for 3 we need

[tex]\sqrt{-\sqrt{3}+(9+\sqrt{3})}[/tex]

So what is the radical

[tex]\sqrt{3+8\sqrt{7+4\sqrt{3}}}[/tex] closest to? 2.7, 5.7 or 10.7?

Although I find it hard to believe, the original expression actually does come out exactly to a small integer value.

RGV
 


Ray Vickson said:
Although I find it hard to believe, the original expression actually does come out exactly to a small integer value.

RGV

The surds inside surds quickly lose their value! :smile:

What I find even more amazing is infinitely nested surds such as

[tex]\sqrt{10+\sqrt{10+\sqrt{10...}}}=\frac{1+\sqrt{41}}{2}\approx 3.7[/tex]

Which is a lot smaller than you'd initially guess!
 


Pranav-Arora said:
Start by writing 7+4√3 as 4+4√3+3 which can be simplified to (2+√3)^2.

Ingenious Pranav! :cool: And the same method can be applied again to get a small integer as result.

ehild
 
  • #10


Pranav-Arora said:
Start by writing 7+4√3 as 4+4√3+3 which can be simplified to (2+√3)^2.

ehild said:
Ingenious Pranav! :cool: And the same method can be applied again to get a small integer as result.

ehild
Yes, Pranav-Arora !

I'm glad to see you figured it out before I saw this thread and racked my brain over this. (Of course, then I racked my brain over whether it's racked or wracked .)
 
  • #11


Thanks ehild and SammyS! :blushing:
 
  • #12


Awesome solution pranav , can't believe i missed that. i got the answer 2 , thank you. btw which city are you from ?
 
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