What is the Value of a for Continuity in This Function?

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Homework Help Overview

The discussion revolves around determining the value of "a" for a piecewise function to ensure continuity across the entire real line. The function is defined as f(x) = { (x+a), x≠a and 8, x=a.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the function's definition and the conditions for continuity, particularly focusing on the limit as x approaches a and the value of the function at that point. There are attempts to equate expressions and clarify the reasoning behind continuity.

Discussion Status

Participants are actively engaging with the problem, exploring the implications of their calculations and questioning the reasoning behind the continuity conditions. Some guidance has been provided regarding the need to show that the limit equals the function value at x=a, but there remains uncertainty about the explanation of these steps.

Contextual Notes

There is a noted confusion regarding the definitions and conditions of the piecewise function, particularly how to articulate the reasoning for continuity at the point where x=a.

Torshi
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Finding the value of "a"

Homework Statement


Determine the value of "a" such that the function is continuous on the whole real line. You must clearly demonstrate why your choice of satisfies the definition of continuity


Homework Equations



f(x) = { (x+a), x≠a and 8, x=a


The Attempt at a Solution



x+a = 8
a+a = 8
2a=8
a=4

Then from there what do I do? Plug 4 into the first function?
The 8, x=a --> is that undefined or limit does not exist?
 
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Torshi said:
Then from there what do I do? Plug 4 into the first function?
Right

And show that the limit for x->4 is the same as the value at x=4. That can be done in 1-2 lines.
 


mfb said:
Right

And show that the limit for x->4 is the same as the value at x=4. That can be done in 1-2 lines.

x+a = 8
x+4 = 8
x=4?
 


Those lines might need an explanation, but the general idea looks good.
 


mfb said:
Those lines might need an explanation, but the general idea looks good.

That's what I don't understand.

I don't know how to explain the reasoning
Because for the first function x≠a and for 8 x=a which makes since in regards to 4+4 = 8 since a=4 and x=a
 


f(x) = x+a, if x≠a and 8, if x=a

For f to be continuous at x = a, it must be true that f(a) = ##\lim_{x \to a} f(x)##

So we must have ##\lim_{x \to a} f(x) = 8##
##\lim_{x \to a} f(x) = \lim_{x \to a} (x + a) = 2a##

Hence 2a = 8, or a = 4.
 

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