What is the Vector Equation of Planes?

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SUMMARY

The discussion focuses on the vector equation of planes, specifically addressing the solution to a homework problem involving augmented matrices and reduced row echelon form (RREF). The user presents an augmented matrix, Aug, and its RREF, demonstrating the steps taken to solve for the intersection of two planes. Key insights include the importance of the cross product of normals, which indicates the direction of the line of intersection between the planes.

PREREQUISITES
  • Understanding of vector equations and planes in three-dimensional space
  • Familiarity with augmented matrices and RREF techniques
  • Knowledge of cross products and their geometric interpretations
  • Basic linear algebra concepts, including systems of equations
NEXT STEPS
  • Study the properties of vector equations of planes in 3D geometry
  • Learn about the application of the cross product in determining line intersections
  • Explore advanced techniques in solving systems of linear equations using matrix methods
  • Investigate the geometric interpretation of RREF in the context of linear transformations
USEFUL FOR

Students studying linear algebra, geometry enthusiasts, and anyone looking to deepen their understanding of vector equations and their applications in three-dimensional space.

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Homework Statement


I'm at (iii) of the question.
attachment.php?attachmentid=23937&stc=1&d=1267121346.jpg


Homework Equations





The Attempt at a Solution


I've got the different ans.
<br /> \[<br /> Aug=<br /> \left( {\begin{array}{cccc}<br /> 2 &amp; -1 &amp; 1 &amp; 5 \\<br /> 3 &amp; 1 &amp; -5 &amp; 6 \\<br /> \end{array} } \right)<br /> \]<br />

<br /> \[<br /> rref=<br /> \left( {\begin{array}{cccc}<br /> 1 &amp; 0 &amp; \frac{4}{5} &amp; \frac{11}{5} \\<br /> 0 &amp; 1 &amp; \frac{-13}{5} &amp; \frac{-3}{5} \\<br /> \end{array}} \right)<br /> \]<br />
 

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Hint: The cross product of the normals is in the direction of the line of intersection. (Why?)
 


LCKurtz said:
Hint: The cross product of the normals is in the direction of the line of intersection. (Why?)

i'm at part 3 . Thanks by the way. I've got my doubts cleared. (=
 

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