What is the volume of the shipping box?

  • Context: MHB 
  • Thread starter Thread starter mathdad
  • Start date Start date
  • Tags Tags
    Box Volume
Click For Summary
SUMMARY

The volume of the shipping box filled with pastry boxes is determined by the height of the pastry boxes. Each pastry box measures 1 cubic foot, and the shipping box is 3 feet high, allowing for 6 pastry boxes in the bottom layer. The calculation for the shipping box's volume is not simply 18 cubic feet; it is expressed as V_S = 6 * (h_S / h_P) = 18 / h_P, indicating that the volume is inversely proportional to the height of the pastry boxes. This mathematical relationship is based on eighth-grade algebra principles.

PREREQUISITES
  • Understanding of basic volume calculations
  • Familiarity with algebraic expressions and inverse variation
  • Knowledge of geometric concepts related to cubical shapes
  • Ability to interpret word problems in mathematics
NEXT STEPS
  • Study the principles of volume calculation for different geometric shapes
  • Learn about inverse variation and its applications in algebra
  • Practice solving word problems in mathematics to improve comprehension
  • Explore the properties of cubical and rectangular prisms in geometry
USEFUL FOR

Students, educators, and anyone interested in improving their understanding of volume calculations and algebraic concepts, particularly in the context of geometric word problems.

mathdad
Messages
1,280
Reaction score
0
A shipping box is filled with pastry boxes. Each pastry box measures 1 cubic foot. The shipping box is 3 feet high. The bottom layer of the shipping box can fit 6 pastry boxes. What is the volume of the shipping box?

Do I simply multiply 1 by 3 by 6 to get 18 cubic feet?
 
Mathematics news on Phys.org
RTCNTC said:
A shipping box is filled with pastry boxes. Each pastry box measures 1 cubic foot. The shipping box is 3 feet high. The bottom layer of the shipping box can fit 6 pastry boxes. What is the volume of the shipping box?

Do I simply multiply 1 by 3 by 6 to get 18 cubic feet?

That would be assuming the pastry boxes are cubical. If we don't make that assumption, then all we know is:

$$w_P\ell_P h_P=1$$

Now we also know:

$$w_S\ell_S=6w_P\ell_P=\frac{6}{h_P}$$

And so the volume of the shipping box is:

$$V_S=6\frac{h_S}{h_P}=\frac{18}{h_P}$$

So, we see that the volume of the shipping box depends on the height of the pastry boxes, in an inverse variation. :D
 
MarkFL said:
That would be assuming the pastry boxes are cubical. If we don't make that assumption, then all we know is:

$$w_P\ell_P h_P=1$$

Now we also know:

$$w_S\ell_S=6w_P\ell_P=\frac{6}{h_P}$$

And so the volume of the shipping box is:

$$V_S=6\frac{h_S}{h_P}=\frac{18}{h_P}$$

So, we see that the volume of the shipping box depends on the height of the pastry boxes, in an inverse variation. :D

I hope to someday understand math at your level.
 
I'm sure that MarkFL is proficient in mathematics at a very high level. But the mathematics he used on this problem is about eighth grade algebra.
 
HallsofIvy said:
I'm sure that MarkFL is proficient in mathematics at a very high level. But the mathematics he used on this problem is about eighth grade algebra.

You are right but word problems are a BIG PROBLEM for me at any grade level after 6th grade. There is no need for the put down.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
Replies
4
Views
1K
  • · Replies 29 ·
Replies
29
Views
4K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 8 ·
Replies
8
Views
9K
  • · Replies 16 ·
Replies
16
Views
4K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 15 ·
Replies
15
Views
3K
Replies
4
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K