What Is the Volume Ratio of Concrete to Styrofoam for a Floating Bridge Pontoon?

Click For Summary
SUMMARY

The discussion focuses on calculating the volume ratio of concrete to Styrofoam for a floating bridge pontoon, specifically in the context of a pontoon that maintains 34.3% of its volume above water. The densities of concrete and Styrofoam are established as 2200 kg/m³ and 50 kg/m³, respectively. The derived density of the pontoon is calculated to be 657 kg/m³, leading to the equation c*2200 + s*50 = 657, where c represents the volume of concrete and s represents the volume of Styrofoam. This equation is essential for determining the correct volume ratio to achieve the desired buoyancy.

PREREQUISITES
  • Understanding of buoyancy principles and Archimedes' principle
  • Knowledge of density calculations and unit conversions
  • Familiarity with algebraic equations and solving for variables
  • Basic concepts of material properties, specifically concrete and Styrofoam densities
NEXT STEPS
  • Research buoyancy calculations in fluid mechanics
  • Study the properties of concrete and Styrofoam in engineering applications
  • Learn about the design and construction of floating structures
  • Explore advanced algebra techniques for solving systems of equations
USEFUL FOR

Engineers, architects, and students involved in civil engineering, particularly those focusing on floating bridge design and material selection for buoyant structures.

sona1177
Messages
171
Reaction score
1

Homework Statement


In many locations, such as Lake Washington in Seattle, floating bridges are preferable to conventional bridges. Such a bridge can be constructed out of concrete pontoons, which are essentially concrete boxes filled with air, Styrofoam, or another extremely low-density material. Suppose a floating bridge pontoon is constructed out of concrete and Styrofoam, which have densities of 2200 kg/m3 and 50.0 kg/m3. What must the volume ratio of concrete to Styrofoam be if the pontoon is to float with 34.3% of its overall volume above water?

Homework Equations


Fbuoyancy-mg=o

The Attempt at a Solution


Fbuoy-mg=o
p(fluid)gV(displaced fluid)=p(platoon)g(Vplatoon)
Vfluid/Vplatoon=p(platoon)/p(fluid)=.343
so p(platoon)/p(fluid)=.343
p(plattoon)=p(fluid) *.343
1000 * .343=343 kg/m^3=density of platoon.

Where do i go from here?
 
Physics news on Phys.org
I didn't understand that! But I think something has gone wrong.
Say the density was half that of water. Then 50% of the pontoon would stick out above the water. If you want a little less to stick out (34%), it would be a little more dense then that. More than half the density of water (1000) - probably 657 rather than 343.

Say you have 1 cubic meter of pontoon. Let c be the volume of the concrete and s the volume of styrafoam. Then
c*2200 + s*50 = 657.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
6K