What is the weight percent of NH3 in the window cleaner?

[Mag]

[SOLVED] titration need help getting started

A 10.231g sample of window cleaner containing ammonia was diluted with 39.466g of water. Then 4.676g of solution was titrated with 14.22mL of 0.1063 M HCl to reach a bromocresol green endpoint. Find the weight percent of NH3 (FW 17.031) in the cleaner.

I keep trying to find someway of getting the 4.676g solution to a volume amount so i can find the mmol of the analyte.

thanks
mag

 

[Bystander]

(snip)Find the weight percent of NH3 (FW 17.031) in the cleaner.(snip)

Do you need to calculate a volume?

 

[chem_tr]

Then 4.676g of solution was titrated with 14.22mL of 0.1063 M HCl to reach a bromocresol green endpoint.

You may start from here, as this sentence tells you that their millimole amounts are equal. You can find millimoles by multiplying volume by concentration, as \displaystyle mL\times \frac {mmol}{mL} gives \displaystyle mmol. If 4.676 g of that solution is equal to the millimoles of \displaystyle NH_3, you can calculate a weight percentage from there.