What is the Work Done by a Pitcher on a Baseball?

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Homework Help Overview

The discussion revolves around calculating the work done by a pitcher on a baseball, given the speed of the baseball and its mass. The context is rooted in the principles of physics, specifically relating to work and energy.

Discussion Character

  • Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to use the kinetic energy formula to determine the work done, expressing confusion about their result. Other participants question the calculations and suggest reviewing the steps taken.

Discussion Status

The discussion has seen participants sharing their calculations and verifying each other's work. There is a recognition of an error in the original calculation, leading to a corrected value being presented. However, there is no explicit consensus on the overall approach or final outcome.

Contextual Notes

Participants are working under the assumption that air resistance can be ignored, and there is a focus on ensuring the correct application of the kinetic energy formula.

goalieguy
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A baseball leaves a pitcher's hand at a speed of 41.0 m/s. The mass of the baseball is 0.142 kg . Ignore air resistance. How much work has the pitcher done on the ball in throwing it?

I've tried using (1/2)mv^2, but there has got to be something weird going on, or i could just be using the wrong equation


thanks for any and all help :smile:
 
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i work it out and get the same thing every time i have tried it.
2.911 Joules is the answer I get, and WebAssign says that it is incorrect.
 
How are you getting that answer? Show what you did.
 
sorry

Sorry about not showing all the work.

I just take the givens: v=41.0 m/s m=0.142 kg

Then I plug it in to: [tex]\frac{m*v^2}{2}[/tex]

[tex]\frac{41*0.142}{2}[/tex]



That is the answer i come up with (2.911 Joules)
 
square your 41, boy!
 
duh. thanks i knew i was doing something completely dumb.
always got to forget the easy part.

right answer = 119.351 Joules

thanks a lot
 

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