What is the work done by a radial force in this situation?

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Homework Help Overview

The discussion revolves around calculating the work done by a radial force as a particle moves along a circular path. The problem involves understanding the relationship between the direction of the force and the motion of the particle.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the work done using the formula for work and considers the distance traveled along a semicircular path. Some participants question the relevance of the radial force in relation to the tangential direction of the particle's motion.

Discussion Status

Participants are exploring the implications of the radial force being perpendicular to the direction of motion. There is an ongoing examination of how this affects the work done, with hints provided to guide understanding without reaching a consensus.

Contextual Notes

There is a suggestion that the work done by the radial force may be zero due to its perpendicular relationship with the particle's instantaneous direction. The discussion reflects uncertainty about the definitions and implications of radial versus tangential forces.

dinhjeffrey
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Homework Statement



http://img26.imageshack.us/i/1113001.jpg/

#11

Homework Equations


C = 2πr
w=fd


The Attempt at a Solution


it travels from point 1 to 2 so its half a circle so the distance is πR.
πRF = w
so i would guess its D.
but the answer is A) zero. i do not know why it is zero though.
 
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Hint: the force is radial, but which direction is the particle at ? (radial, tangential or other)
 
rock.freak667 said:
Hint: the force is radial, but which direction is the particle at ? (radial, tangential or other)

tangential, oh so the work done would be by the tangential force, not the radial force?
 
dinhjeffrey said:
tangential, oh so the work done would be by the tangential force, not the radial force?

No, there is only the radial force, but the instantaneous direction of the particle is given by the direction of the tangent.

So if the force is perpendicular to the direction, what is the work ?
 

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