What is the x-value at which the body's velocity is 5.0 m/s?

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Homework Help Overview

The problem involves a 1.9 kg body moving along the positive x-axis under the influence of a force with an x component defined as Fx = -6x N. The initial condition states that the body's velocity at x = 3.0 m is 8.0 m/s. The discussion centers on determining the body's velocity at x = 4.0 m and finding the positive x-value where the velocity is 5.0 m/s.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of work done between two positions and its relation to changes in kinetic energy. There are questions regarding the initial conditions of the force acting on the body and the implications of the force's direction on the final velocity.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the problem. Some guidance has been offered regarding the relationship between force, work, and velocity, but there is no explicit consensus on the correct approach or solution.

Contextual Notes

There are questions about the starting point of the force's action and the implications of the negative force on the body's velocity. The original poster expresses frustration over repeated attempts to solve the problem correctly.

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The only force acting on a 1.9 kg body as it moves along the positive x-axis has an x component Fx = - 6x N, where x is in meters. The velocity of the body at x = 3.0 m is 8.0 m/s.

(a) What is the velocity of the body at x = 4.0 m?

well work is the integral of the f(x) function, so its -3x^2. Knowing that I can get the work done from x=3 to x=4. which is -3*9 and -3*16. after omitting the sign, which I figured I need to do after about an hour of this problem, I get a net change of 21J. so I plug that into 1/2MVf^2-1/2MVi^2 and get 1/2M(Vf^2-Vi^2)=21J

21J/(.5*1.9Kg)=Vf^2-Vi^2
22.105+Vi^2=Vf^2
Vf=sqrt(22.105+8^2)

this yields me an answer of 9.28 m/s
I must have done this problem about 8 times now, and I can't get it right.



(b) At what positive value of x will the body have a velocity of 5.0 m/s?
 
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Does the force begin to act the object where x=0?
 
I don't really understand what you are trying to say?
 
heyy f is in negative direction vfinal must be less than 8m/s
 

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