What is the Young's modulus of a nylon rope used for climbing?

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SUMMARY

The Young's modulus of a nylon rope used for climbing can be calculated using the formula E = (F * L) / (A * ΔL), where F is the force applied, L is the original length, A is the cross-sectional area, and ΔL is the elongation. For a nylon rope that is 41m long, with a diameter of 0.4 cm, supporting a 97kg climber, the calculated Young's modulus is approximately 82.46 x 108 Pa. This value is derived from the force exerted by the climber, which is 950.6 N (97 kg * 9.8 m/s2), and the rope's cross-sectional area of 0.0001256 m2.

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Homework Statement




For safety climbing, a mountaineer uses a nylon rope that is 41m long and 0,4 cm in diameter. When supporting a 97kg climber, the rope elongates 1,8m. Find its Young’s modulus. The acceleration of gravity is 9,8 m/s2

a) 82,46 x 108 Pa
b) 17,18 x 108 Pa
c) 25 x 106 Pa
d) 86 x 10 6 Pa


Homework Equations





The Attempt at a Solution

 
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Last edited:
Pietro, please use one thread per HW problem. This cuts down on the confusion when folks want to reply to your posts.

Also, you must show an attempt at solution of your HW problem per the forum rules.
 

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