What Matrix Transformation Projects a 3D Planar Shape onto the XY Plane?

[weetabixharry]

I have a (3 x N) matrix of column rank 2. If each column is treated as a point in 3-space, then connecting the points draws out some planar shape.

What operation can I apply such that this planar shape is transformed onto the x-y axis, so that the shape is exactly the same, but is now described fully by x-y coordinates in a (2 x N) matrix?

I feel like there should be a (2 x 3) matrix that would do this, but I can't figure out what it should be. (I have a hunch that I'm looking for a mapping that is isometric and conformal... some kind of rotation?). Also, I'd like to be able to generalise to higher dimensions.

 

[weetabixharry]

I think I may have found a solution, but would appreciate any further discussion... since my understanding is rather weak. I basically started thinking about pseudoinverses and figured I wanted a pseudoinverse of something orthonormal, to avoid distorting my shape (?).

Let's call my (3 x N) matrix A. To get an orthonormal basis spanning the (2D) column space, I eigendecompose AA^T and take the eigenvectors associated with the 2 largest eigenvalues, denoted by the (3 x 2) matrix E₂.

Finally, I left-multiply A by the pseudoinverse of E₂:

A_2D = E₂⁺A

which seems to give the desired 2D representation.

 

[weetabixharry]

A_2D = E₂⁺A

which seems to give the desired 2D representation.

Of course, this can be simplified as:\begin{eqnarray*}<br /> \mathbf{A}_{2D} &amp;=&amp;\mathbf{E}_{2}^{+}\mathbf{A} \\<br /> &amp;=&amp;\left( \mathbf{E}_{2}^{T}\mathbf{E}_{2}\right)^{-1} \mathbf{E}_{2}^{T}\mathbf{A%<br /> } \\<br /> &amp;=&amp;\mathbf{E}_{2}^{T}\mathbf{A}<br /> \end{eqnarray*}
However, I still don't really have an intuitive idea for why this works. Perhaps I should re-ask the question in Linear Algebra.