What maximum power must the motor provide?

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The discussion revolves around calculating the power required by a winch motor to pull a loaded ore car up an inclined mine shaft. The car, with a mass of 950 kg, accelerates to a speed of 2.20 m/s in 12 seconds before moving at a constant speed. The necessary power when the car is at constant speed is determined to be 10.2 kW, while the maximum power required is 10.6 kW. Additionally, the total energy transferred out of the motor by work by the time the car reaches the end of the 1,250 m track is 5.82 MJ. Participants seek clarification on how to calculate the pulling force and its relationship to power.
stupif
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1. A loaded ore car has a mass of 950 kg and rolls on rails with negligible friction. It starts from rest
and is pulled up a mine shaft by a cable connected to a winch. The shaft is inclined at 30.0°
above the horizontal. The car accelerates uniformly to a speed of 2.20 m/s in 12.0 s and then
continues at constant speed. (a) What power must the winch motor provide when the car is
moving at constant speed? (b) What maximum power must the motor provide? (c) What total
energy transfers out of the motor by work by the time the car moves off the end of the track,
which is of length 1 250 m?
( Ans : (a) 10.2 kW (b) 10.6 kW (c) 5.82 MJ )

2,power = (mass x acceleration x distance)/ time
= (950kg x (2.2/12=0.183m/s^2) x distance )/ 12s

how to find the distance??



The Attempt at a Solution

 
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I'm not sure which part you are attempting to solve. Starting with part a, what's the force exerted by the cable? What power must it exert?
 


i am finding this answer (a) What power must the winch motor provide when the car is
moving at constant speed?
 


So answer my question: What force is exerted by the cable? And how does force relate to power?
 


pulling force...power = workdone / time, workdone = force x distance
 


stupif said:
pulling force...power = workdone / time, workdone = force x distance
OK, so what's the pulling force?
 


dont know
 


stupif said:
dont know
You'll have to figure it out. Hint: constant speed.
 

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