What Minimum Speed Must Jane Have to Swing Across the River?

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SUMMARY

To determine the minimum speed Jane must have to swing across a 60.0 m river while overcoming a horizontal wind force of 120 N, the problem involves calculating the potential energy (PE) and kinetic energy (KE) using the equations PE = mgh and KE = 1/2mv². Given Vernie's mass of 45.0 kg and the rope length of 45.0 m at an angle of 60.0°, the calculations yield the necessary speed for both the initial swing and the return swing with Charlie, whose mass is 75.0 kg. The solution requires applying trigonometric principles to adjust the rope length based on the angle.

PREREQUISITES
  • Understanding of potential energy (PE) and kinetic energy (KE) equations
  • Basic knowledge of trigonometry, specifically sine and cosine functions
  • Familiarity with forces acting on objects in motion
  • Concept of conservation of energy in physics
NEXT STEPS
  • Calculate the effective length of the rope using L = L - (Lcosθ)
  • Explore the implications of wind force on swinging dynamics
  • Investigate the conservation of energy in complex systems
  • Review similar physics problems involving pendulum motion and forces
USEFUL FOR

Physics students, educators, and anyone interested in mechanics and energy conservation principles in real-world applications.

alevis
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Homework Statement


Vernie, whose mass is 45.0 kg, needs to swing across a river filled with crocodiles in order to rescue Charlie,whose mass is 75.0 kg. However, she must swing into a constant horizontal wind force on a vine that is
initially at an angle of θ with the vertical. The width of the river between them is D = 60.0 m, F = 120 N, Length of

the rope L = 45.0 m, and θ = 60.0°.
(a) With what minimum speed must Jane begin her swing in order to just make it to the other side?
(b) Once the rescue is complete, Vernie and Charlie must swing back across the river. With what minimum

speed must they begin their swing?



Homework Equations


L=L-(Lcosθ)
KE = 1/2mv2
PE = mgh.


The Attempt at a Solution


PE = KE
mgh = 1/2mv2
 
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